6 Evaluate te (t² + 3) (t² + 7) dt using the Fundamental Theorem of Calculus, Part 2. Enter only exact answers. (1² + 3)(t² + 7)dt = help (numbers)
6 Evaluate te (t² + 3) (t² + 7) dt using the Fundamental Theorem of Calculus, Part 2. Enter only exact answers. (1² + 3)(t² + 7)dt = help (numbers)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Hey can some explain this HW problem?
![**Problem Statement:**
Evaluate the integral \(\int_{-8}^{-6} (t^2 + 3)(t^2 + 7) \, dt\) using the Fundamental Theorem of Calculus, Part 2. Enter only exact answers.
**Expression:**
\[
\int_{-8}^{-6} (t^2 + 3)(t^2 + 7) \, dt = \boxed{\phantom{a}}
\]
Help (numbers): Placeholder for assistance or guidance on calculating the integral.
**Explanation:**
This problem involves evaluating a definite integral using the Fundamental Theorem of Calculus, which connects differentiation with integration. The theorem allows us to evaluate the integral by finding an antiderivative of the function and then calculating the difference of its values at the upper and lower limits of integration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3667c4e2-dfba-4518-b7aa-6b434ae74977%2F9ca0e839-a8e0-4257-8a36-2f2426a72708%2Fmayfwk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Evaluate the integral \(\int_{-8}^{-6} (t^2 + 3)(t^2 + 7) \, dt\) using the Fundamental Theorem of Calculus, Part 2. Enter only exact answers.
**Expression:**
\[
\int_{-8}^{-6} (t^2 + 3)(t^2 + 7) \, dt = \boxed{\phantom{a}}
\]
Help (numbers): Placeholder for assistance or guidance on calculating the integral.
**Explanation:**
This problem involves evaluating a definite integral using the Fundamental Theorem of Calculus, which connects differentiation with integration. The theorem allows us to evaluate the integral by finding an antiderivative of the function and then calculating the difference of its values at the upper and lower limits of integration.
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