6 cm4 cmWhat is the electric field inside the insulatorat a distance of 4 cm? The permeability offree space is 8.85419 x 10 12 C/N/m?.Answer in units of N/C.What is the electric field at 12 cm?Answer in units of N/C.How much work must you do to bring0.035 µC test charge from 12 cm to 4 cm?Answer in units of J.a A long cylindrical insulator has a uniformcharge density of 0.66 µC/m and a radius of36 cm.

Answered: 6 cm 4 cm What is the electric field…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

6 cm
4 cm
What is the electric field inside the insulator
at a distance of 4 cm? The permeability of
free space is 8.85419 x 10 12 C/N/m?.
Answer in units of N/C.
What is the electric field at 12 cm?
Answer in units of N/C.
How much work must you do to bring
0.035 µC test charge from 12 cm to 4 cm?
Answer in units of J.
a

A long cylindrical insulator has a uniform
charge density of 0.66 µC/m and a radius of
3
6 cm.

Expert Solution

Step 1

Given:

Radius of the long cylinder, L = 6 cm = 0.06 m

charge density, $ρ = 0.66 μC / m^{3}$

radius of the outside cylinder, r = 12 cm = 0.12 m

Solution:

We know that, the charge inside the cylinder with radius, $r > R$ will be :

$\begin{array}{rcl} Q & = & ρ V \\ = & 0.66 \times 10^{- 6} \times π \times R^{2} \times L \\ = & 0.66 \times 10^{- 6} \times π \times {(0.06 m)}^{2} \times L - 1 \end{array}$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions