(6) C3H¬CI 6. 1 2 PPM 4 1

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
Problem 119QRT
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do a IR spectra analysis and draw the molecular structure. Provide a well-explained solution.

(6) C3H¬CI
6.
1
2
PPM
4
1
Transcribed Image Text:(6) C3H¬CI 6. 1 2 PPM 4 1
Expert Solution
Step 1

The NMR spectrum provides the following details about the structure of the molecules:

  • The number of signals: The number of signals gives information about the different types of hydrogen atoms.
  • Position of signal: The position of the signal tells us about the electronic environment of hydrogen.
  • splitting of signal: Splitting of the signal tells us about the number of neighboring hydrogen atom present. If the number of the neighboring hydrogen atom is n then the signal split in (n+1) peak.
  • Area of signal: The area of the signal provides information about the number of hydrogen atoms responsible for the signal.
Step 2

The given molecule gives two signals in the NMR spectrum and it confirms the presence of two types of the hydrogen atom in the molecules.

  1. Septet at 3.7 ppm due to one hydrogen with six neighbouring hydrogen (septet = (n+1) = 6+1 = 7).
  2. Doublet at 1.6 ppm is due to one hydrogen with one neighbouring hydrogen atom (doublet = (1+1) = 1+1 = 2).

The molecular formula of the compound is C3H7Cl. The total hydrogen atom in the molecule is seven. Seven hydrogen atoms divided into two sets (6+1). Six hydrogens are the same type confirms the presence of two CH3 groups attached with the same carbon.

On the basis of the above structure the structure of the compound is as follows:

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