6) A particular reaction has the following rate constant at different temperatures: Temperature (°C) k (s¹) Temperature (K) 1/T (K) 6.78 x 10-4 0.134 -52 33 In (k) a. Convert the temperature to kelvin, find 1/T (K), and take the natural log of the rate constant and complete the chart above. b. Plot 1/T (K) in the x-axis and In (k) in the y-axis. This is the linear form of the Arrhenius Equation.
6) A particular reaction has the following rate constant at different temperatures: Temperature (°C) k (s¹) Temperature (K) 1/T (K) 6.78 x 10-4 0.134 -52 33 In (k) a. Convert the temperature to kelvin, find 1/T (K), and take the natural log of the rate constant and complete the chart above. b. Plot 1/T (K) in the x-axis and In (k) in the y-axis. This is the linear form of the Arrhenius Equation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

Transcribed Image Text:6) A particular reaction has the following rate constant at different temperatures:
Temperature (°C)
k (s¹)
Temperature (K)
1/T (K)
6.78 x 10-4
0.134
-52
33
a. Convert the temperature to kelvin, find 1/T (K), and take the natural log of the rate constant and complete the
chart above.
In (k)
b. Plot 1/T (K) in the x-axis and In (k) in the y-axis. This is the linear form of the Arrhenius Equation.
C. Find the slope of the line and then calculate the activation energy of the reaction.
d. Use the 2-point Arrhenius Equation to find the rate constant at T = 0 °C.
Expert Solution

Step 1
We now the Arrhenius equation for activation energy determination.
ln(k2/k1) = Ea/R x (1/T1 - 1/T2)
where,
Ea = the activation energy of the reaction in J/mol
R = the ideal gas constant = 8.3145 J/K·mol
T1 and T2 = absolute temperatures (in Kelvin)
k1 and k2 = the reaction rate constants at T1 and T2
So it is very important equation for activation energy determination
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