6- A conductor of 0.5 mm diameter wire has a resistance of 300 2. Find the resistance of the same length of wire if its diameter were doubled. A) 302 B)150 2 C) 75 Q D) 300 N 7- Use Nodal method for the circuit in fig.4, the equation in node a & b will be 2v 0.5N а 0. 1250 3V 0.2N 0.25N P =? fig.4 1V. Va(50) – V½(10) = 8 Va(34) – V½(110) = 11 A) -V«(10) + V½(25) = -107 В) -Va(150) + Vp(25) = -107 Va(35) – V,(11) = 10 Va(34) – V,(10) = = 16 %3D C) -V«(100) + V,(2. 5) D) = -17 (-v«(10) + V,(25) = = -17 0.050

6- A conductor of 0.5 mm diameter wire has a resistance of 300 2. Find the resistance of the same length of wire if its diameter were doubled. A) 302 B)150 2 C) 75 Q D) 300 N 7- Use Nodal method for the circuit in fig.4, the equation in node a & b will be 2v 0.5N а 0. 1250 3V 0.2N 0.25N P =? fig.4 1V. Va(50) – V½(10) = 8 Va(34) – V½(110) = 11 A) -V«(10) + V½(25) = -107 В) -Va(150) + Vp(25) = -107 Va(35) – V,(11) = 10 Va(34) – V,(10) = = 16 %3D C) -V«(100) + V,(2. 5) D) = -17 (-v«(10) + V,(25) = = -17 0.050

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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