-6 -6 {(3.-1,3) 2 = 2t(2,2,- £)) c) C> -1 4 -6 -4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Find the eigenvalues and corresponding eigenvector spaces for the following matrices
![The text presents a matrix and its associated eigenvalues and eigenvectors.
Matrix \( C \):
\[
C = \begin{bmatrix}
5 & -6 & -6 \\
-1 & 4 & 2 \\
3 & -6 & -4
\end{bmatrix}
\]
The eigenvalues and their corresponding eigenvectors are given as follows:
- For eigenvalue \(\lambda = 1\), the corresponding eigenvector is \( t(3, -1, 3) \).
- For eigenvalue \(\lambda = 2\), the corresponding eigenvector is \( t(2, 2, -1) \).
Here, \( t \) is a scalar, indicating that the eigenvectors can be multiplied by any scalar to obtain a valid eigenvector.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3bc59c38-daef-422b-8804-1bd4f924eec5%2Ff76b0a3b-a05a-4c15-b727-5c273bd719e7%2Fi6j9j9_processed.png&w=3840&q=75)
Transcribed Image Text:The text presents a matrix and its associated eigenvalues and eigenvectors.
Matrix \( C \):
\[
C = \begin{bmatrix}
5 & -6 & -6 \\
-1 & 4 & 2 \\
3 & -6 & -4
\end{bmatrix}
\]
The eigenvalues and their corresponding eigenvectors are given as follows:
- For eigenvalue \(\lambda = 1\), the corresponding eigenvector is \( t(3, -1, 3) \).
- For eigenvalue \(\lambda = 2\), the corresponding eigenvector is \( t(2, 2, -1) \).
Here, \( t \) is a scalar, indicating that the eigenvectors can be multiplied by any scalar to obtain a valid eigenvector.
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