*6-4. Determine the force in each member of the truss and state if the members are in tension or compression 3 kip H. -2 kip 3 kip NG 8 ft F +1.5 kip- 4 ft A |C |D F10 ft →10 ft 10 ft +10 ft D
*6-4. Determine the force in each member of the truss and state if the members are in tension or compression 3 kip H. -2 kip 3 kip NG 8 ft F +1.5 kip- 4 ft A |C |D F10 ft →10 ft 10 ft +10 ft D
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![**Problem 6-4: Truss Analysis**
**Objective:** Determine the force in each member of the truss and state whether each member is in tension or compression.
**Diagram Explanation:**
The truss depicted in the diagram consists of a series of interconnected members and joints. It is supported at points A (a pin support) and E (a roller support), ensuring stability and resistance to external forces. The diagram includes dimensions and external loads applied to the truss:
- **External Loads:**
- A downward load of 2 kip (kilo-pound) acting vertically at point H.
- A downward load of 3 kip acting vertically at points G and F.
- **Span Dimensions:**
- The horizontal distances between points A to B, B to C, C to D, and D to E are each 10 ft.
- The vertical distance from the base to point I is 4 ft, to point H is 8 ft.
- **Support Reactions:**
- A pin support at point A resists both horizontal and vertical forces.
- A roller support at point E resists only vertical forces.
**Truss Members:**
- Members such as AB, BC, CD, DE, etc., connect the joints and maintain structural integrity.
To solve for the forces in each member, methods such as the method of joints or method of sections can be utilized. Forces are calculated to determine if the members are in tension (pulling apart) or compression (pushing together).
Understanding this truss analysis involves applying principles of static equilibrium where the sum of forces and moments in the system must be zero. This problem serves as a fundamental exercise in structural analysis, crucial for engineering applications.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7fcffe20-88c0-46a7-a9a5-147a481f673b%2F9d141e3f-7930-4ded-b2e1-a7d0ad000a84%2Fjmcfghe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 6-4: Truss Analysis**
**Objective:** Determine the force in each member of the truss and state whether each member is in tension or compression.
**Diagram Explanation:**
The truss depicted in the diagram consists of a series of interconnected members and joints. It is supported at points A (a pin support) and E (a roller support), ensuring stability and resistance to external forces. The diagram includes dimensions and external loads applied to the truss:
- **External Loads:**
- A downward load of 2 kip (kilo-pound) acting vertically at point H.
- A downward load of 3 kip acting vertically at points G and F.
- **Span Dimensions:**
- The horizontal distances between points A to B, B to C, C to D, and D to E are each 10 ft.
- The vertical distance from the base to point I is 4 ft, to point H is 8 ft.
- **Support Reactions:**
- A pin support at point A resists both horizontal and vertical forces.
- A roller support at point E resists only vertical forces.
**Truss Members:**
- Members such as AB, BC, CD, DE, etc., connect the joints and maintain structural integrity.
To solve for the forces in each member, methods such as the method of joints or method of sections can be utilized. Forces are calculated to determine if the members are in tension (pulling apart) or compression (pushing together).
Understanding this truss analysis involves applying principles of static equilibrium where the sum of forces and moments in the system must be zero. This problem serves as a fundamental exercise in structural analysis, crucial for engineering applications.
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