Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Find the value of X and Y in the following right
![**Title: Solving Right Triangles**
**Introduction:**
In this lesson, we will explore the properties of a right-angled triangle and the methods to solve for unknown sides using trigonometric principles.
**Diagram Analysis:**
The diagram shows a right-angled triangle with the following properties:
- There is a right angle (\(90^\circ\)) at the vertex opposite the hypotenuse.
- One of the angles is \(30^\circ\).
- The hypotenuse has a length of \(6\sqrt{3}\).
- The sides opposite and adjacent to the \(30^\circ\) angle are labeled \(x\) and \(y\), respectively.
**Step-by-Step Solution:**
1. **Identify Known Values:**
- Hypotenuse (\(c\)): \(6\sqrt{3}\)
- Angle (\(\theta\)): \(30^\circ\)
2. **Use the Sine and Cosine Functions:**
The sine function for \(\theta = 30^\circ\):
\[
\sin(30^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{x}{6\sqrt{3}}
\]
We know that \(\sin(30^\circ) = \frac{1}{2}\), thus:
\[
\frac{1}{2} = \frac{x}{6\sqrt{3}}
\]
Solving for \(x\):
\[
x = \frac{1}{2} \times 6\sqrt{3} = 3\sqrt{3}
\]
The cosine function for \(\theta = 30^\circ\):
\[
\cos(30^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{y}{6\sqrt{3}}
\]
We know that \(\cos(30^\circ) = \frac{\sqrt{3}}{2}\), thus:
\[
\frac{\sqrt{3}}{2} = \frac{y}{6\sqrt{3}}
\]
Solving for \(y\):
\[
y = \frac{\sqrt{3}}{2} \times 6\sqrt{3} = 3 \times 3 = 9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4bb5a6dd-97cd-4d93-a8e0-dafecb13cdf7%2F6c8fe48f-a8fa-4fa2-9219-bb2cd42edaad%2Felw0g1d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Solving Right Triangles**
**Introduction:**
In this lesson, we will explore the properties of a right-angled triangle and the methods to solve for unknown sides using trigonometric principles.
**Diagram Analysis:**
The diagram shows a right-angled triangle with the following properties:
- There is a right angle (\(90^\circ\)) at the vertex opposite the hypotenuse.
- One of the angles is \(30^\circ\).
- The hypotenuse has a length of \(6\sqrt{3}\).
- The sides opposite and adjacent to the \(30^\circ\) angle are labeled \(x\) and \(y\), respectively.
**Step-by-Step Solution:**
1. **Identify Known Values:**
- Hypotenuse (\(c\)): \(6\sqrt{3}\)
- Angle (\(\theta\)): \(30^\circ\)
2. **Use the Sine and Cosine Functions:**
The sine function for \(\theta = 30^\circ\):
\[
\sin(30^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{x}{6\sqrt{3}}
\]
We know that \(\sin(30^\circ) = \frac{1}{2}\), thus:
\[
\frac{1}{2} = \frac{x}{6\sqrt{3}}
\]
Solving for \(x\):
\[
x = \frac{1}{2} \times 6\sqrt{3} = 3\sqrt{3}
\]
The cosine function for \(\theta = 30^\circ\):
\[
\cos(30^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{y}{6\sqrt{3}}
\]
We know that \(\cos(30^\circ) = \frac{\sqrt{3}}{2}\), thus:
\[
\frac{\sqrt{3}}{2} = \frac{y}{6\sqrt{3}}
\]
Solving for \(y\):
\[
y = \frac{\sqrt{3}}{2} \times 6\sqrt{3} = 3 \times 3 = 9

Transcribed Image Text:### Right Triangle with a 30° Angle
The diagram shown is a right triangle with one of its angles measuring 30 degrees. The triangle includes the following components:
1. **Right Angle**: The triangle has one 90° angle, indicated by the small square on the left-hand side of the triangle.
2. **30° Angle**: One of the acute angles in the triangle measures 30°, as labeled on the diagram.
3. **Legs of the Triangle**:
- The leg adjacent to the 30° angle is labeled as **x**.
- The leg opposite the 30° angle is labeled as **y**.
4. **Hypotenuse**: The hypotenuse, which is the side opposite the right angle and the longest side of the triangle, is labeled as \(5\sqrt{3}\).
### Explanation of the Diagram
In trigonometry, a 30-60-90 triangle has a standardized ratio for the lengths of its sides. When the shortest side (adjacent to the 30° angle) is known, the lengths of the other sides can be determined using this ratio:
- Hypotenuse: \( 2 \times (\text{shortest side}) \)
- The side opposite the 30° angle is half of the hypotenuse.
- The side opposite the 60° angle (next to the 30° angle) is \( \sqrt{3} \times (\text{shortest side}) \).
Given that the hypotenuse (\(5\sqrt{3}\)) relates to this standard ratio, the triangle's measurements conform to these principles.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Recommended textbooks for you

Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,

Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning

Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,

Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning