6) - -2+4メ-5 1 --2 (x-2x)-5 = Coefcientofメー42 FE)--2(x²-2x+4)-5+4 H)= -2 (x-2)-1RIam getting this But the answeris f&) = -2(x-2)-3 why?
6) - -2+4メ-5 1 --2 (x-2x)-5 = Coefcientofメー42 FE)--2(x²-2x+4)-5+4 H)= -2 (x-2)-1RIam getting this But the answeris f&) = -2(x-2)-3 why?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the vertex form of each quadratic function by completing the square.
I attach two picture showing how I did the both problems. For #2 question I just want you to check if I did it right. And #5 I am getting a different answer can you show me step by step how you got the answer.
Thank You
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