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(6, 2). The vertex of a parabola is and the equation of its directrix is y = 4. What is the equation of this parabola in standard form? (x - 6)2 =8 (y – 2) (y – 2)2 = -8 (x – 6) | • (y – 2)2 =8 (x – 6) (x – 6) = -8 (y – 2)

(6, 2). The vertex of a parabola is and the equation of its directrix is y = 4. What is the equation of this parabola in standard form? (x - 6)2 =8 (y – 2) (y – 2)2 = -8 (x – 6) | • (y – 2)2 =8 (x – 6) (x – 6) = -8 (y – 2)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The vertex of a parabola is \( (6, 2) \), and the equation of its directrix is \( y = 4 \). What is the equation of this parabola in standard form? Options: - \( (x - 6)^2 = 8(y - 2) \) - \( (y - 2)^2 = -8(x - 6) \) - \( (y - 2)^2 = 8(x - 6) \) - \( (x - 6)^2 = -8(y - 2) \)
Transcribed Image Text:The vertex of a parabola is \( (6, 2) \), and the equation of its directrix is \( y = 4 \). What is the equation of this parabola in standard form? Options: - \( (x - 6)^2 = 8(y - 2) \) - \( (y - 2)^2 = -8(x - 6) \) - \( (y - 2)^2 = 8(x - 6) \) - \( (x - 6)^2 = -8(y - 2) \)
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