6-2 Let X be a set, let QCX be fixed and let e-(QU(x): xEX-Q). Then e is a cover of X by subsets of X and has the same cardinality as X-Q.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.7: Relations
Problem 11E: Let be a relation defined on the set of all integers by if and only if sum of and is odd. Decide...
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6-2 Let X be a set, let QCX be fixed and let
e=(QU(x): XEX-Q}. Then e is a cover of X by subsets of X
and has the same cardinality as X-Q.
Transcribed Image Text:6-2 Let X be a set, let QCX be fixed and let e=(QU(x): XEX-Q}. Then e is a cover of X by subsets of X and has the same cardinality as X-Q.
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