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5x2 f(x) = V4x2 + 5 Find f' (x), and then evaluate f' at x = 1 and x -1. f'(1) = | f'(-1) =

5x2 f(x) = V4x2 + 5 Find f' (x), and then evaluate f' at x = 1 and x -1. f'(1) = | f'(-1) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The task involves finding the derivative of the function \( f(x) = \frac{5x^2}{\sqrt{4x^2 + 5}} \) and then evaluating the derivative, \( f'(x) \), at \( x = 1 \) and \( x = -1 \). The text reads: "Find \( f'(x) \), and then evaluate \( f' \) at \( x = 1 \) and \( x = -1 \). \[ f'(1) = \quad \] \[ f'(-1) = \quad \]" The problem prompts you to compute the derivative of the given function and substitute \( x = 1 \) and \( x = -1 \) into the derivative to find the corresponding values.
Transcribed Image Text:The task involves finding the derivative of the function \( f(x) = \frac{5x^2}{\sqrt{4x^2 + 5}} \) and then evaluating the derivative, \( f'(x) \), at \( x = 1 \) and \( x = -1 \). The text reads: "Find \( f'(x) \), and then evaluate \( f' \) at \( x = 1 \) and \( x = -1 \). \[ f'(1) = \quad \] \[ f'(-1) = \quad \]" The problem prompts you to compute the derivative of the given function and substitute \( x = 1 \) and \( x = -1 \) into the derivative to find the corresponding values.
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