Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Precalculus with Trig: Section 7.4
I need help better understanding this topic of Pythagorean identity. Can you help me?
![Below are trigonometric identities that can be explored for educational purposes:
**Equation 59:**
\[
\tan \theta + \frac{\cos \theta}{1 + \sin \theta} = \sec \theta
\]
**Equation 61:**
\[
\frac{\tan \theta + \sec \theta - 1}{\tan \theta - \sec \theta + 1} = \tan \theta + \sec \theta
\]
**Equation 63:**
\[
\frac{\tan \theta - \cot \theta}{\tan \theta + \cot \theta} = \sin^2 \theta - \cos^2 \theta
\]
These equations involve trigonometric functions and can be used to practice identities, transformations, and simplifications in trigonometry. Each equation provides an opportunity to verify or derive new expressions using known trigonometric identities.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea56b2d3-976b-48ba-b1de-ef5a4d536379%2F7d75f4c0-a237-4a19-9ca7-ad40f8b2b3bd%2Flvnr6i_processed.png&w=3840&q=75)
Transcribed Image Text:Below are trigonometric identities that can be explored for educational purposes:
**Equation 59:**
\[
\tan \theta + \frac{\cos \theta}{1 + \sin \theta} = \sec \theta
\]
**Equation 61:**
\[
\frac{\tan \theta + \sec \theta - 1}{\tan \theta - \sec \theta + 1} = \tan \theta + \sec \theta
\]
**Equation 63:**
\[
\frac{\tan \theta - \cot \theta}{\tan \theta + \cot \theta} = \sin^2 \theta - \cos^2 \theta
\]
These equations involve trigonometric functions and can be used to practice identities, transformations, and simplifications in trigonometry. Each equation provides an opportunity to verify or derive new expressions using known trigonometric identities.
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