58 A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 42,000 kg/s. The tip velocity of the turbine blade is measured to be 250 km/h. If 180 kW power is produced by the turbine, determine (a) the average velocity of the air and (b) the conversion effi- ciency of the turbine. Take the density of air to be 1.31 kg/m³. Answer: a)5.22 m/sec_ b) 31.46 %_
58 A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 42,000 kg/s. The tip velocity of the turbine blade is measured to be 250 km/h. If 180 kW power is produced by the turbine, determine (a) the average velocity of the air and (b) the conversion effi- ciency of the turbine. Take the density of air to be 1.31 kg/m³. Answer: a)5.22 m/sec_ b) 31.46 %_
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![2.
58 A wind turbine is rotating at 15 rpm under steady
winds flowing through the turbine at a rate of 42,000 kg/s.
The tip velocity of the turbine blade is measured to be 250
km/h. If 180 kW power is produced by the turbine, determine
(a) the average velocity of the air and (b) the conversion effi-
ciency of the turbine. Take the density of air to be 1.31
kg/m³.
Answer: _a)5.22 m/sec_ b) 31.46 %](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65daeccd-7e5c-40c3-9cd8-2e5bc13b665a%2F115e0322-eb45-4e3b-a4db-ede1e53ce758%2F8eg7y6p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2.
58 A wind turbine is rotating at 15 rpm under steady
winds flowing through the turbine at a rate of 42,000 kg/s.
The tip velocity of the turbine blade is measured to be 250
km/h. If 180 kW power is produced by the turbine, determine
(a) the average velocity of the air and (b) the conversion effi-
ciency of the turbine. Take the density of air to be 1.31
kg/m³.
Answer: _a)5.22 m/sec_ b) 31.46 %
![2.
N=15rpm
m-42,000
v= 250 km
W= 180kw
P=1.21.
Solution
m² PAVAN
d= Ux40
TIN
2
h: Output
input
Find
a) Vaus
(b) n
(250 x)×40
Varg = 42,000 k
n
ITIS
(1.313) () (08.42 m2
190 kW
=
=
= 31.467.
eo 4 45
88.42m
= 5.22 m
×42,000x(S.22²
'S
2
180kw
S72.22 (
50.3146%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65daeccd-7e5c-40c3-9cd8-2e5bc13b665a%2F115e0322-eb45-4e3b-a4db-ede1e53ce758%2Fvqubkek_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2.
N=15rpm
m-42,000
v= 250 km
W= 180kw
P=1.21.
Solution
m² PAVAN
d= Ux40
TIN
2
h: Output
input
Find
a) Vaus
(b) n
(250 x)×40
Varg = 42,000 k
n
ITIS
(1.313) () (08.42 m2
190 kW
=
=
= 31.467.
eo 4 45
88.42m
= 5.22 m
×42,000x(S.22²
'S
2
180kw
S72.22 (
50.3146%
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