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57 ILW A block of mass mı : clined at angle 0 = 30.0° is connected by a cord over a massless, Frictionless pulley to a second block of mass m2 = 2.30 kg (Fig. 5-52). What are (a) the magnitude of the acceleration of each plock, (b) the direction of the acceleration of the hanging block, and (c) the.tension in the cord? 3.70 kg on a frictionless plane in- %3D

57 ILW A block of mass mı : clined at angle 0 = 30.0° is connected by a cord over a massless, Frictionless pulley to a second block of mass m2 = 2.30 kg (Fig. 5-52). What are (a) the magnitude of the acceleration of each plock, (b) the direction of the acceleration of the hanging block, and (c) the.tension in the cord? 3.70 kg on a frictionless plane in- %3D

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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•57 ILW A block of mass m1 clined at angle 0 - 30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.30 kg (Fig. 5-52). What are (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the.tension in the cord? 3.70 kg on a frictionless plane in- Figure 5-52 Problem 57.
Transcribed Image Text:•57 ILW A block of mass m1 clined at angle 0 - 30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.30 kg (Fig. 5-52). What are (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the.tension in the cord? 3.70 kg on a frictionless plane in- Figure 5-52 Problem 57.
Expert Solution
Step 1

a) By fbd of system 

m2g - m1gSinθ = (m1+m2)a 

a = (2.3 - 3.7×Sin30)×9.8 / (2.3+3.7) 

a = 0.735 m/s2 

 

b) hanging block moves downward 

 

c) by fbd of m2 

m2g - T = m2a 

T = m2(g-a) = 2.3×(9.8-0.735)

T = 20.85 N

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