55 SSM A Nichrome heater dissipates 500 W when the applied potential difference is 110 V and the wire temperature is 800°C. What would be the dissipation rate if the wire temperature were held at 200°C by immersing the wire in a bath of cooling oil? The applied potential difference remains the same, and a for Nichrome at 800°C is 4.0 × 10-4K-1
55 SSM A Nichrome heater dissipates 500 W when the applied potential difference is 110 V and the wire temperature is 800°C. What would be the dissipation rate if the wire temperature were held at 200°C by immersing the wire in a bath of cooling oil? The applied potential difference remains the same, and a for Nichrome at 800°C is 4.0 × 10-4K-1
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Question
For problem 55 calculate the power in watts at
200 C if the power at 800 C is 829 W. (Answer in 5 sig. figs.)

Transcribed Image Text:55 SSM A Nichrome heater dissipates 500 W when the applied
potential difference is 110 V and the wire temperature is 800°C.
What would be the dissipation rate if the wire temperature were
held at 200°C by immersing the wire in a bath of cooling oil? The
applied potential difference remains the same, and a for Nichrome
at 800°C is 4.0 × 10-4K-¹.

Transcribed Image Text:QUESTION 3
For problem 26.55 calculate the power in watts at
200 C if the power at 800 C is 829 W. (5 sig. figs.)
Expert Solution
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Step 1
be the resistance at the higher temperature and let be the resistance
at the lower temperature .
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Solved in 2 steps
