53in². What is the radius of ⒸI? S E Set-up: A = P Therefore... e area of sector PAL is 142.55ft², and the radius PA = 11 ft. the m PL in degrees. Set-up: 360° Therefore... 2 п 360° ²π

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question
2. Suppose in I that m SET = 195° and the area of sector SIT is
333.53in². What is the radius of I?
S
E
Set-up:
L
Therefore...
P
3. If the area of sector PAL is 142.55ft2, and the radius PA = 11 ft.
Find the m PL in degrees Set-up:
2π
360°
Therefore...
360°
2 п
=
Transcribed Image Text:2. Suppose in I that m SET = 195° and the area of sector SIT is 333.53in². What is the radius of I? S E Set-up: L Therefore... P 3. If the area of sector PAL is 142.55ft2, and the radius PA = 11 ft. Find the m PL in degrees Set-up: 2π 360° Therefore... 360° 2 п =
Activity: Area of a Sector
R
Sector
A
sector area =
I. Study the given to complete the set up for the solution then
find the measure of the unknown.
N
arc measure
1. Suppose in OR that m AN = 45° and the radius is 12m. What is the
area of sector NRA? (round off the answer up to 2 decimal places)
Set-up:
2 п
360°
Therefore...
².r²π
360°
Transcribed Image Text:Activity: Area of a Sector R Sector A sector area = I. Study the given to complete the set up for the solution then find the measure of the unknown. N arc measure 1. Suppose in OR that m AN = 45° and the radius is 12m. What is the area of sector NRA? (round off the answer up to 2 decimal places) Set-up: 2 п 360° Therefore... ².r²π 360°
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