53.5 mol of an ideal gas occupies 79.5 L at 311 K, what is the pressure of the gas? pressure: atm

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Problem Statement:**

If 53.5 mol of an ideal gas occupies 79.5 L at 311 K, what is the pressure of the gas?

**Solution:**

pressure: [Answer box] atm

**Explanation:**

To solve this problem, you can use the Ideal Gas Law:

\[ PV = nRT \]

Where:
- \( P \) is the pressure of the gas.
- \( V \) is the volume of the gas (79.5 L).
- \( n \) is the number of moles (53.5 mol).
- \( R \) is the ideal gas constant (0.0821 L·atm/mol·K).
- \( T \) is the temperature in Kelvin (311 K).

Rearrange the equation to solve for \( P \):

\[ P = \frac{nRT}{V} \]

Plug in the values:

\[ P = \frac{53.5 \times 0.0821 \times 311}{79.5} \] 

Calculate the pressure to find the answer in atm.
Transcribed Image Text:**Problem Statement:** If 53.5 mol of an ideal gas occupies 79.5 L at 311 K, what is the pressure of the gas? **Solution:** pressure: [Answer box] atm **Explanation:** To solve this problem, you can use the Ideal Gas Law: \[ PV = nRT \] Where: - \( P \) is the pressure of the gas. - \( V \) is the volume of the gas (79.5 L). - \( n \) is the number of moles (53.5 mol). - \( R \) is the ideal gas constant (0.0821 L·atm/mol·K). - \( T \) is the temperature in Kelvin (311 K). Rearrange the equation to solve for \( P \): \[ P = \frac{nRT}{V} \] Plug in the values: \[ P = \frac{53.5 \times 0.0821 \times 311}{79.5} \] Calculate the pressure to find the answer in atm.
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