52-2)180--2)180とろ (2x+プト3メナ2×+108けると=540 7x+197354 7x=343 X=49 12 108 とろとし 0 L4=82 LC=34タミ147 LD=249=98 3x 2X LE=108 213= 2x+7-105 17) m Z3 = (2x- 6)(x- 4) mZ5= 5(5x + 3)- (2x²-42) Determine the value of x so that line I will be parallel to line m. >m mL3+mL521800 8/レ 3/4 5/6 23 イメニ130-81 (2x-6)(x-5)+5(5x+3)-(2x?2)=/io 2A-8x-6x+24+25x+5-2x-42=D190 18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ statements reasons M. 19) Given: PS = RQ; PO = RS Prove: PQ|| SR statements reasons
52-2)180--2)180とろ (2x+プト3メナ2×+108けると=540 7x+197354 7x=343 X=49 12 108 とろとし 0 L4=82 LC=34タミ147 LD=249=98 3x 2X LE=108 213= 2x+7-105 17) m Z3 = (2x- 6)(x- 4) mZ5= 5(5x + 3)- (2x²-42) Determine the value of x so that line I will be parallel to line m. >m mL3+mL521800 8/レ 3/4 5/6 23 イメニ130-81 (2x-6)(x-5)+5(5x+3)-(2x?2)=/io 2A-8x-6x+24+25x+5-2x-42=D190 18) Given: XM bisects YXZ and ZYMZ. Prove: XM bisects ZYKZ statements reasons M. 19) Given: PS = RQ; PO = RS Prove: PQ|| SR statements reasons
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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