52. Will the code run as expected to dispense items purchased in a vending machine? DISPLAY("Please insert money and make a selection") REPEAT UNTIL (amt Paid a cost) { ELSE } IF { amt Paid INPUT( ) DISPLAY("Please enter $, cost- ant Paid, "to make your purchase") amt Paid amt Paid INPUT ( ) (amt Paid> cost) DISPLAY ("Your change is $, (cost - amt Paid)) ELSE ( } Dispense (item) Dispense (change) Dispense (item) DISPLAY("Enjoy your selection!") (A) Yes, the code works as expected. (B) The REPEAT UNTIL loop is an infinite loop. (C) The calculation of the amount of change to return is incorrect. (D) The > sign should be < in the IF statement. 53. What is displayed after the following code runs? rate-10 hours - 40 totalPay-0 overtimePay -- IF (hours > 40 DISPLAY("You earned overtime pay.") DISPLAY("Regular Pay $, hours rate) (A) You carned overtime pay. (B) Regular Pay = $40 * 10 (C) 400 (D) Regular Pay=$400 Page 9 / 12
52. Will the code run as expected to dispense items purchased in a vending machine? DISPLAY("Please insert money and make a selection") REPEAT UNTIL (amt Paid a cost) { ELSE } IF { amt Paid INPUT( ) DISPLAY("Please enter $, cost- ant Paid, "to make your purchase") amt Paid amt Paid INPUT ( ) (amt Paid> cost) DISPLAY ("Your change is $, (cost - amt Paid)) ELSE ( } Dispense (item) Dispense (change) Dispense (item) DISPLAY("Enjoy your selection!") (A) Yes, the code works as expected. (B) The REPEAT UNTIL loop is an infinite loop. (C) The calculation of the amount of change to return is incorrect. (D) The > sign should be < in the IF statement. 53. What is displayed after the following code runs? rate-10 hours - 40 totalPay-0 overtimePay -- IF (hours > 40 DISPLAY("You earned overtime pay.") DISPLAY("Regular Pay $, hours rate) (A) You carned overtime pay. (B) Regular Pay = $40 * 10 (C) 400 (D) Regular Pay=$400 Page 9 / 12
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 20PE
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