1.52. Show that if x[n] is periodic with period N, thenn+NNno +N(a) x[k]= *Ik];2 x[k];(b) *Ik] = 2 x[k]k=nok=no+Nk=0k=no

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Answered: 52. Show that if x[n] is periodic with…

52. Show that if x[n] is periodic with period N, then no +N (b) E ×Ik]= > x[k] n+N N (a) 2 x[k]= 2 x[k]; k=no k=no +N k=0 k=no

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

1.52. Show that if x[n] is periodic with period N, then
n+N
N
no +N
(a) x[k]= *Ik];
2 x[k];
(b) *Ik] = 2 x[k]
k=no
k=no+N
k=0
k=no

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