52. Show that if x[n] is periodic with period N, then no +N (b) E ×Ik]= > x[k] n+N N (a) 2 x[k]= 2 x[k]; k=no k=no +N k=0 k=no
52. Show that if x[n] is periodic with period N, then no +N (b) E ×Ik]= > x[k] n+N N (a) 2 x[k]= 2 x[k]; k=no k=no +N k=0 k=no
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![1.52. Show that if x[n] is periodic with period N, then
n+N
N
no +N
(a) x[k]= *Ik];
2 x[k];
(b) *Ik] = 2 x[k]
k=no
k=no+N
k=0
k=no](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3efd62bd-26bb-4b13-baa0-f32494628224%2F31ea5bd1-a631-491d-8feb-c23c6e3b95fe%2Fh80cwc8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.52. Show that if x[n] is periodic with period N, then
n+N
N
no +N
(a) x[k]= *Ik];
2 x[k];
(b) *Ik] = 2 x[k]
k=no
k=no+N
k=0
k=no
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