College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
Question 52
![(b) the (linear) tangential acceleration, (c) the centripetal
late (a) the angular acceleration,
circular
Th
acceleration just before release, (d) the net force being
averted on the hammer by the athlete just before release.
and (e) the angle of this force with respect to the radius of
the circular motion. Ignore gravity.
an
th
ab
is
e
8-7 Rotational Kinetic Energy
49. (1) An automobile engine develops a torque of 265 m · N at
What is the horsepower of the engine?
50. (I) A centrifuge rotor has a moment of inertia of
bs 3.25 x 10-2 kg m². How much energy is required to bring
3350
rpm.
it from rest to 8750 rpm?
51. (I) Calculate the translational speed of a cylinder when it
reaches the foot of an incline 7.20 m high. Assume it starts
from rest and rolls without slipping.
52. (II) A bowling ball of mass 7.25 kg and radius 10.8 cm rolls
without slipping down a lane at 3.10 m/s. Calculate its total
kinetic energy.
59.
8-
53. (II) Estimate the kinetic energy of the Earth with respect
to the Sun as the sum of two terms, (a) that due to its daily
rotation about its axis, and (b) that due to its yearly revolu-
o tion about the Sun. [Assume the Earth is a uniform sphere
60
with mass =
6.0 x 1024 kg, radius
6.4 X 10° m, and is
1.5 X 108 km from the Sun.]
54. (II) A rotating uniform cylindrical platform of mass 220 kg
and radius 5.5 m slows down from 3.8 rev/s to rest in 16 s
when the driving motor is disconnected. Estimate the power
output of the motor (hp) required to maintain a steady
speed of 3.8 rev/s.
55. (II) A merry-go-round has a mass of 1440 kg and a radius
of 7.50 m. How much net work is required to accelerate it
from rest to a rotation rate of 1.00 revolution per 7.00 s?
1.80 kg
30. 0°
Assume it is a solid cylinder.
34 5 cm and mass m =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb8325a4-2633-4af0-a374-671d985d22c7%2Fbbc3a5ab-bce6-414b-b3b4-e49dcd15357d%2Fw4bylrd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(b) the (linear) tangential acceleration, (c) the centripetal
late (a) the angular acceleration,
circular
Th
acceleration just before release, (d) the net force being
averted on the hammer by the athlete just before release.
and (e) the angle of this force with respect to the radius of
the circular motion. Ignore gravity.
an
th
ab
is
e
8-7 Rotational Kinetic Energy
49. (1) An automobile engine develops a torque of 265 m · N at
What is the horsepower of the engine?
50. (I) A centrifuge rotor has a moment of inertia of
bs 3.25 x 10-2 kg m². How much energy is required to bring
3350
rpm.
it from rest to 8750 rpm?
51. (I) Calculate the translational speed of a cylinder when it
reaches the foot of an incline 7.20 m high. Assume it starts
from rest and rolls without slipping.
52. (II) A bowling ball of mass 7.25 kg and radius 10.8 cm rolls
without slipping down a lane at 3.10 m/s. Calculate its total
kinetic energy.
59.
8-
53. (II) Estimate the kinetic energy of the Earth with respect
to the Sun as the sum of two terms, (a) that due to its daily
rotation about its axis, and (b) that due to its yearly revolu-
o tion about the Sun. [Assume the Earth is a uniform sphere
60
with mass =
6.0 x 1024 kg, radius
6.4 X 10° m, and is
1.5 X 108 km from the Sun.]
54. (II) A rotating uniform cylindrical platform of mass 220 kg
and radius 5.5 m slows down from 3.8 rev/s to rest in 16 s
when the driving motor is disconnected. Estimate the power
output of the motor (hp) required to maintain a steady
speed of 3.8 rev/s.
55. (II) A merry-go-round has a mass of 1440 kg and a radius
of 7.50 m. How much net work is required to accelerate it
from rest to a rotation rate of 1.00 revolution per 7.00 s?
1.80 kg
30. 0°
Assume it is a solid cylinder.
34 5 cm and mass m =
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