52 grams of CuCl2 are reacted with 192 grams of NaNO3.How many moles of NaCl are produced? Answer to twodecimal places. (Hint: find the limiting reactant first!)CuCl2 + 2 NaNO3 Cu(NO3)2 + 2 NaClCuCl, = 134.45 g/molNaNO3 = 84.99 g/mol

Answered: 52 grams of CuCl2 are reacted with 192…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

52 grams of CuCl2 are reacted with 192 grams of NaNO3.
How many moles of NaCl are produced? Answer to two
decimal places. (Hint: find the limiting reactant first!)
CuCl2 + 2 NaNO3 Cu(NO3)2 + 2 NaCl
CuCl, = 134.45 g/mol
NaNO3 = 84.99 g/mol

Expert Solution

Step 1

$g i v e m a s s o f C u C l_{2} = 52 g m o l a r m a s s o f C u C l 2 = 134.45 g t h e r e f o r e, n o o f m o l e s o f C u C l_{2} = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{52}{134.45} = 0.3867 m o l e = 0.39 m o l e a l s o, g i v e n m a s s o f N a N O_{3} = 192 g m o l a r m a s s o f N a N O_{3} = 84.99 g n o o f m o l e s o f N a N O_{3} = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{192}{84.99} = 2.259 o r = 2.26 m o l e$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions