51. Challenge Problem Escape Velocity From physics, the equation for the free-flight trajectory of a satellite launched a distance ro from the center of the earth is given by the polar equation 1 GM. GM. cos e + rovo where M, is the mass of the earth, G is the gravitational constant, and vo is the initial velocity of the satellite. If the initial velocity is equal to the escape velocity (the velocity needed to overcome Earth's gravitational pull) then the resulting trajectory follows a parabolic path. What is the escape velocity?

51. Challenge Problem Escape Velocity From physics, the equation for the free-flight trajectory of a satellite launched a distance ro from the center of the earth is given by the polar equation 1 GM. GM. cos e + rovo where M, is the mass of the earth, G is the gravitational constant, and vo is the initial velocity of the satellite. If the initial velocity is equal to the escape velocity (the velocity needed to overcome Earth's gravitational pull) then the resulting trajectory follows a parabolic path. What is the escape velocity?