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(50%) 3.35 rad/s. em 1: A wheel with a radius of 0.22 m rotates with a constant angular acceleration of 3.98 rad/s². At t=0 the angular velocity of the wheel is @theexpertta.com - tracking id: 5T88-CE-66-41-81D1-44248. In accordance with Expert TA's Terms of Service copying this information to any solutions sharing website is strictly forbidden. so may result in termination of your Expert TA Account. 33% Part (a) What is the angular velocity of the wheel, in radians per second, at t = 8.3 s? w(8.30 s) = rad/s sin() cotan() atan() cosh() cos() tan() asin() acos() acotan() sinh() tanh() cotanh() Degrees O Radians Submit Hint T () 7 8 9 E|**|*| 4 5 6 17. 1 2 3 + 0 VO BACKSPACE Feedback HOME END CLEAR I give up! Feedback: 3% deduction per feedback Hints: 1 for a 3% deduction. Hints remaining: 0 -Because the angular acceleration is constant, a rotational kinematic equation can be used. Start by determining which of the kinematic variables are involved in the problem. Then pick the rotational kinematic equation involving those variables. 33% Part (b) What is the angular displacement of the wheel, in radians, between t=0 s and t = 8.3 s? 0(8.30 s)=2.470 rad X Attempts Remain A 33% Part (c) What is the tangential speed, in meters per second, of a point on the rim of the wheel at t = 8.3 s? Grade Summa Deductions Potential Submissions Attempts rema (5% per attem detailed view 1 2 OC

(50%) 3.35 rad/s. em 1: A wheel with a radius of 0.22 m rotates with a constant angular acceleration of 3.98 rad/s². At t=0 the angular velocity of the wheel is @theexpertta.com - tracking id: 5T88-CE-66-41-81D1-44248. In accordance with Expert TA's Terms of Service copying this information to any solutions sharing website is strictly forbidden. so may result in termination of your Expert TA Account. 33% Part (a) What is the angular velocity of the wheel, in radians per second, at t = 8.3 s? w(8.30 s) = rad/s sin() cotan() atan() cosh() cos() tan() asin() acos() acotan() sinh() tanh() cotanh() Degrees O Radians Submit Hint T () 7 8 9 E|**|*| 4 5 6 17. 1 2 3 + 0 VO BACKSPACE Feedback HOME END CLEAR I give up! Feedback: 3% deduction per feedback Hints: 1 for a 3% deduction. Hints remaining: 0 -Because the angular acceleration is constant, a rotational kinematic equation can be used. Start by determining which of the kinematic variables are involved in the problem. Then pick the rotational kinematic equation involving those variables. 33% Part (b) What is the angular displacement of the wheel, in radians, between t=0 s and t = 8.3 s? 0(8.30 s)=2.470 rad X Attempts Remain A 33% Part (c) What is the tangential speed, in meters per second, of a point on the rim of the wheel at t = 8.3 s? Grade Summa Deductions Potential Submissions Attempts rema (5% per attem detailed view 1 2 OC

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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em 1: A wheel with a radius of 0.22 m rotates with a constant angular acceleration of 3.98 rad/s². At t=0 the angular velocity of the wheel is (50%) 3.35 rad/s. @theexpertta.com - tracking id: 5T88-CE-66-41-81D1-44248. In accordance with Expert TA's Terms of Service copying this information to any solutions sharing website is strictly forbidden. so may result in termination of your Expert TA Account. 33% Part (a) What is the angular velocity of the wheel, in radians per second, at t = 8.3 s? w(8.30 s) = rad/s sin() cotan() atan() cosh() cos() tan() asin() acos() E acotan() sinh() tanh() cotanh() Degrees O Radians Submit Hint T ( ) 7 8 9 14 5 6 7: 1 2 3 + 0 VO BACKSPACE Hints: 1 for a 3% deduction. Hints remaining: 0 -Because the angular acceleration is constant, a rotational kinematic equation can be used. Start by determining which of the kinematic variables are involved in the problem. Then pick the rotational kinematic equation involving those variables. Feedback - HOME END CLEAR I give up! Feedback: 3% deduction per feedback. 33% Part (b) What is the angular displacement of the wheel, in radians, between t = 0s and t = 8.3 s? 0(8.30 s)=2.470 rad X Attempts Remain A 33% Part (c) What is the tangential speed, in meters per second, of a point on the rim of the wheel at t = 8.3 s? Grade Summa Deductions Potential Submissions Attempts rema (5% per attem detailed view 1 2 目
Transcribed Image Text:em 1: A wheel with a radius of 0.22 m rotates with a constant angular acceleration of 3.98 rad/s². At t=0 the angular velocity of the wheel is (50%) 3.35 rad/s. @theexpertta.com - tracking id: 5T88-CE-66-41-81D1-44248. In accordance with Expert TA's Terms of Service copying this information to any solutions sharing website is strictly forbidden. so may result in termination of your Expert TA Account. 33% Part (a) What is the angular velocity of the wheel, in radians per second, at t = 8.3 s? w(8.30 s) = rad/s sin() cotan() atan() cosh() cos() tan() asin() acos() E acotan() sinh() tanh() cotanh() Degrees O Radians Submit Hint T ( ) 7 8 9 14 5 6 7: 1 2 3 + 0 VO BACKSPACE Hints: 1 for a 3% deduction. Hints remaining: 0 -Because the angular acceleration is constant, a rotational kinematic equation can be used. Start by determining which of the kinematic variables are involved in the problem. Then pick the rotational kinematic equation involving those variables. Feedback - HOME END CLEAR I give up! Feedback: 3% deduction per feedback. 33% Part (b) What is the angular displacement of the wheel, in radians, between t = 0s and t = 8.3 s? 0(8.30 s)=2.470 rad X Attempts Remain A 33% Part (c) What is the tangential speed, in meters per second, of a point on the rim of the wheel at t = 8.3 s? Grade Summa Deductions Potential Submissions Attempts rema (5% per attem detailed view 1 2 目
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