50.00 mL of a solution containing both Ni* and Pb2* ions requires 46.32 mL of a 0.02041 M EDTA solution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to mask the nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molarities of the Ni2 and Pb2* ions. acid and
50.00 mL of a solution containing both Ni* and Pb2* ions requires 46.32 mL of a 0.02041 M EDTA solution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to mask the nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molarities of the Ni2 and Pb2* ions. acid and
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:XERCISE IV- 3.
50.00mL of a solution containing both Ni2* and Pb2+ ions requires 46.32 mL of a 0.02041M EDTA
solution for titration of both metals. A second 50.00 mL aliquot is treated with KCN to mask
the nickel and then titrated with 30.28 mL of the same EDTA solution. Calculate the molarities
of the Ni2 and Pb2+ ions.
2. A 0.5745 g sample of an alloy containing principally bismuth and lead is dissolved in nitric acid and
diluted to 250.0 mL in a volumetric flask. A 50.00 mL aliquot is withdrawn, the pH adjusted to 1.5,
and the bismuth titrated with 30.26 mL of 0.01024 M EDTA. The pH of the solution is then
increased to 5.0 and the lead titrated with 20.42 mL of the same EDTA solution. Calculate the
percentages of lead and bismuth in the alloy.
3. A standard solution of EDTA is prepared, and by titration each mL is found to complex with the
Mg in 10.0 mL of a solution containing 0.300 g of MgCl2 per liter. A 100 mL pipetful of a certain
well water is found to require 8.60 mL of the standard EDTA. With the knowledge that the
conventional method of expressing water hardness in terms of ppm of CaCO3 regardless of the
nature of the cations and anions actually present, what is the hardness of the well water?
4. A 60.00 mL of buffered solution (pH 10) containing Zn and Nit ions (from a chip sample) is
analyzed using EDTA titration with EBT as indicator. The following data were recorded:
M of EDTA = 0.05204 M
=D41.97 mL
= 15.16 mL
How many mmoles of Zn and Ni were present in the solution ? If the weight of the chip is
V of EDTA for ZN2+
V of EDTA for Ni2+
1.000 g, give the % Zn and % Ni in the original sample.
-54-
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