50 Two small spherical conductors are suspended from light- weight vertical insulating threads. The conductors are brought into contact (Fig. P23.50, left) and released. Afterward, the conductors and threads stand apart as shown at right. a. C What can you say about the charge of each sphere? b. N Use the data given in Figure P23.50 to find the tension in each thread. c. N Find the magnitude of the charge on each sphere. 0.500 m ( = 0.750 m e 0.750 m 23.4° 23.4° 0.350 g 0.350 g FIGURE P23.50
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- Which of the following statements is true? O The magnitude of the electrostatic force exerted by one point charge on another point charge is inversely proportional to the magnitude of the charges . O The electric field points away from a positive charge and toward a negative charge O The magnitude of the electrostatic force exerted by one point charge on another point charge directly proportional to the square of the distance between them. O The electric field due to a group of point charges can be obtained by taking the algebraic sum of individual electric fields.Question is attached.I am working on some physics homework and am stuck on this one. Any help would be great, thanks!
- A system of 1565 particles, each of which is either an electron or a proton, has a net charge of -3.952×10-17 C. Part A How many electrons are in this system? 15. ΑΣΦ N₂ = Submit Request Answer Part B What is the mass of this system? Π| ΑΣΦ M = Submit Request Answer www ? ? pod kgTwo small metallic spheres, each of mass m = 0.15 g, are suspended as pendulums by light strings from a common point as shown in the figure below. The spheres are given the same electric charge, and it is found that they come to equilibrium when each string is at an angle of 0 = 4.8° with the vertical. If each string has length L = 40.0 cm, what is the magnitude of the charge on each sphere? L m Your response differs from the correct answer by more than 10%. Double check your calculations. nCA +4.2×10-⁹ C charged object is 6.9 cm along a horizontal line toward the right of a -3.3×10-9 C charged object. Part A Determine the E field at a point 4.0 cm to the left of the negative charge.
- A uniformly charged thin ring has radius 15.0 cm and total charge 20.0 nC. An electron is placed on the ring's axis a distance 30.0 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A ring of charge. ▶ Part A Part B Find the speed of the electron when it reaches the center of the ring. Express your answer in meters per second. VE ΑΣΦ V= Submit Provide Feedback Request Answer Constants ? m/s Next >Two small identical conducting spheres are placed with their centers 0.42 m apart. One is given a charge of 10 ✕ 10-9 C, the other a charge of -14 ✕ 10-9 C. (a) Find the electrostatic force exerted on one sphere by the other. N(b) The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached. NB10
- A-1.5-μC charge experiences a 10î -N electric force in a certain electric field. Part A What force would a proton experience in the same field? Express your answer in newtons. ΠΠ ΑΣΦ Fx = ? NA Van de Graaff generator has a 0.045 mC charge on its conducting spherical terminal. a.What is the magnitude of the electric field 2.7 m from the center of the terminal of the Van de Graaff generator? Since that distance is greater than the radius of the terminal, the field is the same as that due to the same charge concentrated at the center. Give your answer in newtons per coulomb. b. At this distance, what is the magnitude of the force that the field exerts on a 2.1 μC point charge on the Van de Graaff generator's belt? Give your answer in newtons.C) The lightning is formed when current starts to flow between the two spheres. Explain at least two different non obvious facts about what is going on inside and around these “lightning bolts”. If a direction is involved with your facts, give that direction.