50) Find the equation of the line tangent to f(x)=3x² -5x+8 at x = 2. Answer in slope-intercept form.

Q: Determine the slope of the curve y = x² + 2x at the point (-1, -3) on the curve.

A: We have to determine the slope of the given curve at the point .

Q: Write the equation of a line tangent to the graph of f(x) = -2x³ + 5æ3 – 5x — — —1 3 at the point x…

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Q: m = 4 and x-intercept of -2 in point-slope form

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Q: How would get a slope-intercept equation with y=1/5x-4 and (-4,-8)?

A: See the details solution in below

Q: Give the slope-intercept form of a line perpendicular to y=2/3x+1 passing through (-2,3)

A: Given equation of line: y = 23x+1and Point (-2, 3)

Q: O Find the equation of the line tangent to the graph of f(x) = 7x + 3x? – 4x - 8 a %3D

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Q: Line Tengent to X-2 y= X + 6 at point (-4,-3)

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Q: x-2y=8 in slope intercept form?

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Q: Find the slope-intercept equation of the line through (9, 2) with slope -2/3.

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Q: Write and equation for a line perpendicular to f(x)= 5x - 1 and passing through the point (5,20)

A: