50 Electrical Technology ww 2 V Is Vs 24 V + 4Ω Fig. 1.104 Fig. 1.100 5. The value of resistance R' shown in the given Fig. 1.101 is 9. The linear network as in Fig. 1.105 has only resistors. If I, = 8A and I, = 12 A; V is found to be 80 V. V = 0 when I, =-8A and I = 4A. Then the value of V when I, = 1, = 10 A, is 4 A 10 V R 50 v = NETWORK Fig. 1.101 (a) 3.5 2 (c) 1 N (b) 2.5 2 Fig. 1.105 (d) 4.5 N (b) 50 (d) 100 V (a) 25 V (ESE 2001) (c) 75 V 6. For the circuit shown in the given Fig. 1.102 the current I is given by (GATE 2003) (ESE 2003) 10. In Fig. 1.106, the value of R is 4Ω 20 14 2 10 ww 5 V 6 At ΙΩΣ 10 V. 3 V 20 100 v 40 V Fig. 1.106 Fig. 1.102 (a) 3 A (b) 2 А (a) 10 2 (b) 18 N (c) 1 A (Pune University 2003) (ESE 2001) 7. The value of V in the circuit shown in the given Fig. 1.103 is (d) zero (c) 24 2 (d) 12 2 (GATE 2003) 11. In the circuit shown in Fig. 1.107, the switch S is closed at time t=0. The voltage across the inductance at t = 0, is (Mumbai University 2003) 3 V ww 10 4F 3A 1 10 V 4 H Fig. 1.103 Fig. 1.107 (a) 1 V (c) 3 V (b) 2 V (d) 4 V (GATE 2003) (ESE 2001) (a) 2 V (c) – 6 V (b) 4 V (d) 8 V (GATE 2003) 12. The rms value of the resultant current in a 8. In the circuit shown in Fig. 1.104, the value wire which carries a de current of 10 A and of V is 0, when I=4A. The value of I when V = 16V, is a sinusoidal alternating current of peak value 20 A is (a) 6 A (c) 10 A (b) 8 A (d) 12 A (GATE 2003) (ESE 2003) (a) 14.1 A (c) 22.4 A (b) 17.3 A (d) 30.0 A (GATE 2004) ww ww

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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50
Electrical Technology
2 Vp.
Is (t
2 2
Vs
24 V=
>42
Fig. 1.104
Fig. 1.100
5. The value of resistance 'R' shown in the
given Fig. 1.101 is
9. The linear network as in Fig. 1.105 has only
resistors. If I, = 8A and I, = 12 A; V is
found to be 80 V. V= 0 when I, =-8A and
I = 4A. Then the value of V when I, = 12
= 10 A, is
62
4 A
10 V
V
50 V
78
R
NETWORK
Fig. 1.101
(b) 2.5 2
(d) 4.5 2
(ESE 2001)
(а) 3.5 Q
Fig. 1.105
(c) 1 Q
(a) 25 V
(b) 50
(c) 75 V
(d) 100 V
6. For the circuit shown in the given Fig. 1.102
(GATE 2003) (ESE 2003)
the current I is given by
10. In Fig. 1.106, the value of R is
ww
14 2
12
10 V
ww
6 A(1
12
3 V
22
100 V
40 V
Fig. 1.102
Fig. 1.106
(а) 3 А
(b) 2 A
(a) 10 2
(b) 18 2
(c) 24 2
(с) 1 А
(Pune University 2003) (ESE 2001)
7. The value of V in the circuit shown in the
given Fig. 1.103 is
(d) zero
(d) 12 2
(GATE 2003)
11. In the circuit shown in Fig. 1.107, the switch
S is closed at time t= 0. The voltage across
the inductance at t = 0", is
(Mumbai University 2003)
3 V
3Ω
12
4F =
3 A 1
103 v
10 V
ЗА
4 H
Fig. 1.103
Fig. 1.107
(a) 1 V
(c) 3 V
(b) 2 V
(d) 4 V
(GATE 2003) (ESE 2001)
(a) 2 V
(с) - 6 V
(b) 4 V
(d) 8 V
(GATE 2003)
12. The rms value of the resultant current in a
8. In the circuit shown in Fig. 1.104, the value
wire which carries a dc current of 10 A and
of V, is 0, when I=4A. The value of I when
V = 16V, is
a sinusoidal alternating current of peak value
20 A is
S
(a) 6 A
(c) 10 A
(b) 8 A
(d) 12 A
(GATE 2003) (ESE 2003)
(a) 14.1 A
(c) 22.4 A
(b) 17.3 A
(d) 30.0 A
(GATE 2004)
ww
Transcribed Image Text:50 Electrical Technology 2 Vp. Is (t 2 2 Vs 24 V= >42 Fig. 1.104 Fig. 1.100 5. The value of resistance 'R' shown in the given Fig. 1.101 is 9. The linear network as in Fig. 1.105 has only resistors. If I, = 8A and I, = 12 A; V is found to be 80 V. V= 0 when I, =-8A and I = 4A. Then the value of V when I, = 12 = 10 A, is 62 4 A 10 V V 50 V 78 R NETWORK Fig. 1.101 (b) 2.5 2 (d) 4.5 2 (ESE 2001) (а) 3.5 Q Fig. 1.105 (c) 1 Q (a) 25 V (b) 50 (c) 75 V (d) 100 V 6. For the circuit shown in the given Fig. 1.102 (GATE 2003) (ESE 2003) the current I is given by 10. In Fig. 1.106, the value of R is ww 14 2 12 10 V ww 6 A(1 12 3 V 22 100 V 40 V Fig. 1.102 Fig. 1.106 (а) 3 А (b) 2 A (a) 10 2 (b) 18 2 (c) 24 2 (с) 1 А (Pune University 2003) (ESE 2001) 7. The value of V in the circuit shown in the given Fig. 1.103 is (d) zero (d) 12 2 (GATE 2003) 11. In the circuit shown in Fig. 1.107, the switch S is closed at time t= 0. The voltage across the inductance at t = 0", is (Mumbai University 2003) 3 V 3Ω 12 4F = 3 A 1 103 v 10 V ЗА 4 H Fig. 1.103 Fig. 1.107 (a) 1 V (c) 3 V (b) 2 V (d) 4 V (GATE 2003) (ESE 2001) (a) 2 V (с) - 6 V (b) 4 V (d) 8 V (GATE 2003) 12. The rms value of the resultant current in a 8. In the circuit shown in Fig. 1.104, the value wire which carries a dc current of 10 A and of V, is 0, when I=4A. The value of I when V = 16V, is a sinusoidal alternating current of peak value 20 A is S (a) 6 A (c) 10 A (b) 8 A (d) 12 A (GATE 2003) (ESE 2003) (a) 14.1 A (c) 22.4 A (b) 17.3 A (d) 30.0 A (GATE 2004) ww
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