5.92 If it takes 10.6 hours for 1.00 L of nitrogen, N2, to ef-fuse through the pores in a balloon, how long would it take for1.00 L of helium, He, to effuse under the same conditions?

Answered: 5.92 If it takes 10.6 hours for 1.00 L…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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5.92 If it takes 10.6 hours for 1.00 L of nitrogen, N2, to ef-
fuse through the pores in a balloon, how long would it take for
1.00 L of helium, He, to effuse under the same conditions?

Expert Solution

Step 1V

Rate of effusion :-

The volume of gas effused per unit time is called rate of effusion .

r = V/t

Graham's law of effusion :-

It states that at constant temperature and pressure the rate of effusion of gas is inversely proportional to square root of its density.

$r \propto \frac{1}{\sqrt{d}} \sin c e d e n s i t y o f g a s i s p r o p o r t i o n a l t o m o l a r m a s s (M) G r a h a m' s l a w c a n a l s o b e w r i t t e n a s r \propto \frac{1}{\sqrt{M}} F o r t w o g a s e s e f f u \sin g u n d e r s i m i l a r c o n d d i t i o n s \frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \frac{V_{1} / t_{1}}{V_{2} / t_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} \frac{V_{1} t_{2}}{V_{2} t_{1}} = \sqrt{\frac{M_{2}}{M_{1}}}$

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