5.92 If it takes 10.6 hours for 1.00 L of nitrogen, N2, to ef- fuse through the pores in a balloon, how long would it take for 1.00 L of helium, He, to effuse under the same conditions?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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5.92 If it takes 10.6 hours for 1.00 L of nitrogen, N2, to ef-
fuse through the pores in a balloon, how long would it take for
1.00 L of helium, He, to effuse under the same conditions?
Transcribed Image Text:5.92 If it takes 10.6 hours for 1.00 L of nitrogen, N2, to ef- fuse through the pores in a balloon, how long would it take for 1.00 L of helium, He, to effuse under the same conditions?
Expert Solution
Step 1V

Rate of effusion :-

The volume of gas effused per unit time is called rate of effusion .

r = V/t 

Graham's law of effusion :-

It states that at constant temperature and pressure the rate of effusion of gas is inversely proportional to square root of its density.

r  1dsince density of gas is proportional to molar mass (M)Graham's law can also be written asr  1MFor two gases effusing under similar condditionsr1r2 = M2M1V1/t1V2/t2 =M2M1 V1t2V2t1 = M2M1

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