Directions: Write the balanced equation for each of the following situations. SHOW ALL OF YOUR WORK ON ATTACHED PAGES, OR IT WILL NOT BE ACCEPTED. In addition, list the reaction type.YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS GO TO COMPLETION.If only STOICHIOMETRY, tell how much of the excess reactant is used!!!! Reaction Typea. Combination Reactionb. Decomposition Reactionc. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reactione. Gaseous Reactionf. Neutralization Reactiong. Combustion Reaction5.92 g of sodium oxalate is reacted with 5.92 of calcium chloridefollow the format used in the image provided. 2. N₂ (g) + 3 H₂ (g) 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant)Grams of Product (List the Product and the Amount): 0.75168 g NH3Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction)1g N₂? g NH3 = 61.802 cg N₂ xLR1 mol N₂ x 2 mol NH3 x28.02 g N₂ 1 mol N₂17.04 g NH3 =1 mol NH31 x 10²2 cg N₂? g NH3 = 61.802 cg H₂ xHow much N₂ remains in the vessel?1g H₂1 x 10² g H₂XXX1 mol H₂2.02 g H₂X2 mol NH3 x 17.04 g NH3 =3 mol H₂1 mol NH30.75168 g NH3 ******* THEORETICAL YIELDYou will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN.? g H₂ USED = 61.802 cg N₂ X 1g N₂1 mol N₂ x28.02 g N₂1 x 10² cg N₂Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED= 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED= 0.48436 g of H₂--LEFT OVER = EXCESS3 mol H₂ x 2.02 g H₂ =1 mol N₂ 1 mol H₂3.3756 g NH30.13366 g H₂

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Answered: 5.92 g of sodium oxalate is reacted…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Directions: Write the balanced equation for each of the following situations. SHOW ALL OF YOUR
WORK ON ATTACHED PAGES, OR IT WILL NOT BE ACCEPTED. In addition, list the reaction type.
YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE
CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS
GO TO COMPLETION.
If only STOICHIOMETRY, tell how much of the excess reactant is used!!!!
Reaction Type
a. Combination Reaction
b. Decomposition Reaction
c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction
d. Precipitation Reaction
e. Gaseous Reaction
f. Neutralization Reaction
g. Combustion Reaction

5.92 g of sodium oxalate is reacted with 5.92 of calcium chloride

follow the format used in the image provided.

2. N₂ (g) + 3 H₂ (g) 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant)
Grams of Product (List the Product and the Amount): 0.75168 g NH3
Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction)
1g N₂
? g NH3 = 61.802 cg N₂ x
LR
1 mol N₂ x 2 mol NH3 x
28.02 g N₂ 1 mol N₂
17.04 g NH3 =
1 mol NH3
1 x 10²2 cg N₂
? g NH3 = 61.802 cg H₂ x
How much N₂ remains in the vessel?
1g H₂
1 x 10² g H₂
X
X
X
1 mol H₂
2.02 g H₂
X
2 mol NH3 x 17.04 g NH3 =
3 mol H₂
1 mol NH3
0.75168 g NH3 ******* THEORETICAL YIELD
You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN.
? g H₂ USED = 61.802 cg N₂ X 1g N₂
1 mol N₂ x
28.02 g N₂
1 x 10² cg N₂
Amount of H₂ Remaining in the Container = H₂ amount given - H₂ amount USED= 0.61802 g H₂ GIVEN - 0.13366 g H₂ USED
= 0.48436 g of H₂--LEFT OVER = EXCESS
3 mol H₂ x 2.02 g H₂ =
1 mol N₂ 1 mol H₂
3.3756 g NH3
0.13366 g H₂

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