Solve and explain so that is easy to understand **Section 5.2.1 Linear Momentum—Nonuniform Flow****5.48** Water is sprayed radially outward over 180° as indicated in Fig. P5.48. The jet sheet is in the horizontal plane. If the jet velocity at the nozzle exit is 30 ft/s, determine the direction and magnitude of the resultant horizontal anchoring force required to hold the nozzle in place.**Figure P5.48 Explanation:**The figure illustrates a nozzle setup where water is being sprayed radially outward in the horizontal plane. Notable dimensions and directions include:- The nozzle exit, from which water is expelled, has a velocity of 30 ft/s.- The radial spread of the water covers 180°.- The diameter of the nozzle is 0.5 inches.- The main body from which water is expelled outward is labeled as 8 inches wide. This horizontal component extends symmetrically about the central nozzle.The task involves calculating the horizontal anchoring force needed to stabilize the nozzle as it sprays water at the specified velocity.

Given data:- Water is sprayed radially outward 180° The given jet velocity at the nozzle exit is, 30 ft/sThe free-body diagram of the given beam:- The force in y direction:- FY=-∫csνρν→n^dAν→=-ν2Cosθν=ν2dA=dθn^=hFy=∫0πν2ρν2CosθRdθFy=ν22ρR∫0πCosθdθFy=ν22ρRSinθ0πFy=ν22ρR×0Fy=0The force in y direction:- Fx=∫csνρν→n^dAν→=ν2Sinθν=ν2Fx=∫0πν22sinθρhRdθFx=ν22ρhR∫0πSinθdθFx=-ν22ρhRcosθ0πFx=-ν22ρhRcosπ-cos0Fx=-ν22ρhR-1-1Fx=2ν22ρhRFx=2×302×1.94×0.512×812Fx=97 lb