### Problem 5.4A cylindrical float has a 10-inch diameter and is 12 inches long. What should be the specific weight of the float material if it is to have 9/10 of its volume below the surface of a fluid with a specific gravity of 1.10?**Solution Steps:**1. **Calculate the volume of the cylindrical float:** - **Volume (V)** = π * (radius^2) * height - Radius = 10 inches / 2 = 5 inches - Height = 12 inches - V = π * (5^2) * 122. **Determine the volume submerged:** - Volume submerged = (9/10) * V3. **Calculate the weight of the displaced fluid:** - Specific gravity of fluid = 1.10 - Specific weight of water (typically) = 62.4 lb/ft³ - Specific weight of fluid = 1.10 * 62.44. **Apply the principle of buoyancy:** - Weight of the float = Weight of the displaced fluid - Specific weight of float = (Weight of float) / (Volume of float)### Detailed Explanation of Graphs/Diagrams (if applicable):In this problem, no graphs or diagrams are provided or necessary. The problem involves calculations based on geometric formulas and principles of buoyancy in fluid mechanics. The steps include calculating the volume of a cylinder, understanding the specific gravity and specific weight formula, and applying the principle of buoyancy to determine the required specific weight of the material.

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5.4 A cylindrical float has a 10-in diameter and is 12 in long. What should be the specific weight of the float material if it is to have 9/10 of its volume below the surface of a fluid with a specific gravity of 1.10? in diameter and 1.2 m 1:1

5.4 A cylindrical float has a 10-in diameter and is 12 in long. What should be the specific weight of the float material if it is to have 9/10 of its volume below the surface of a fluid with a specific gravity of 1.10? in diameter and 1.2 m 1:1

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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### Problem 5.4

A cylindrical float has a 10-inch diameter and is 12 inches long. What should be the specific weight of the float material if it is to have 9/10 of its volume below the surface of a fluid with a specific gravity of 1.10?

**Solution Steps:**

1. **Calculate the volume of the cylindrical float:**
- **Volume (V)** = π * (radius^2) * height
- Radius = 10 inches / 2 = 5 inches
- Height = 12 inches
- V = π * (5^2) * 12

2. **Determine the volume submerged:**
- Volume submerged = (9/10) * V

3. **Calculate the weight of the displaced fluid:**
- Specific gravity of fluid = 1.10
- Specific weight of water (typically) = 62.4 lb/ft³
- Specific weight of fluid = 1.10 * 62.4

4. **Apply the principle of buoyancy:**
- Weight of the float = Weight of the displaced fluid
- Specific weight of float = (Weight of float) / (Volume of float)

### Detailed Explanation of Graphs/Diagrams (if applicable):

In this problem, no graphs or diagrams are provided or necessary. The problem involves calculations based on geometric formulas and principles of buoyancy in fluid mechanics. The steps include calculating the volume of a cylinder, understanding the specific gravity and specific weight formula, and applying the principle of buoyancy to determine the required specific weight of the material.

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