5.33 The paper “Predictors of Complementary Therapy Use Among Asthma Patients: Results of a Primary Care Survey" (Health and Social Care in the Community [2008]: 155–164) i. The probability that an asthma patient responds that conventional medications do not help and that the patient uses complementary therapies. ii. The probability that an asthma patient responds that con- ventional medications do not help and that the patient does not use complementary therapies. ii. The probability that an asthma patient responds that conventional medications usually help or the patient uses complementary therapies. described a study in which each person in a large sample of asthma patients responded to two questions: Question 1: Do conventional asthma medications usu- ally help your symptoms? Question 2: Do you use complementary therapies (such as herbs, acupuncture, aroma therapy) in the treat- ment of your asthma? Suppose that this sample is representative of asthma patients. Consider the following events: E = event that the patient uses complementary therapies F = event that the patient reports conventional medica- tions usually help The data from the sample were used to estimate the follow- ing probabilities: P(E) = 0.146 P(F) = 0.879 P(EN F) = 0.122 a. Use the given probability information to set up a hypo- thetical 1000 table with columns corresponding to E and not E and rows corresponding to F and not F. b. Use the table from Part (a) to find the following

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5.33 The paper "Predictors of Complementary Therapy Use
Among Asthma Patients: Results of a Primary Care Survey"
(Health and Social Care in the Community [2008]: 155–164)
described a study in which each person in a large sample of
asthma patients responded to two questions:
Question 1: Do conventional asthma medications usu-
ally help your symptoms?
Question 2: Do you use complementary therapies (such
as herbs, acupuncture, aroma therapy) in the treat-
ment of your asthma?
i. The probability that an asthma patient responds that
conventional medications do not help and that the
patient uses complementary therapies.
ii. The probability that an asthma patient responds that con-
ventional medications do not help and that the patient
does not use complementary therapies.
iii. The probability that an asthma patient responds that
conventional medications usually help or the patient
uses complementary therapies.
Suppose that this sample is representative of asthma patients.
Consider the following events:
E = event that the patient uses complementary therapies
F = event that the patient reports conventional medica-
tions usually help
The data from the sample were used to estimate the follow-
ing probabilities:
P(E) = 0.146 P(F) = 0.879 P(EN F) = 0.122
a. Use the given probability information to set up a hypo-
thetical 1000 table with columns corresponding to E and
not E and rows corresponding to F and not F.
b. Use the table from Part (a) to find the following
Transcribed Image Text:5.33 The paper "Predictors of Complementary Therapy Use Among Asthma Patients: Results of a Primary Care Survey" (Health and Social Care in the Community [2008]: 155–164) described a study in which each person in a large sample of asthma patients responded to two questions: Question 1: Do conventional asthma medications usu- ally help your symptoms? Question 2: Do you use complementary therapies (such as herbs, acupuncture, aroma therapy) in the treat- ment of your asthma? i. The probability that an asthma patient responds that conventional medications do not help and that the patient uses complementary therapies. ii. The probability that an asthma patient responds that con- ventional medications do not help and that the patient does not use complementary therapies. iii. The probability that an asthma patient responds that conventional medications usually help or the patient uses complementary therapies. Suppose that this sample is representative of asthma patients. Consider the following events: E = event that the patient uses complementary therapies F = event that the patient reports conventional medica- tions usually help The data from the sample were used to estimate the follow- ing probabilities: P(E) = 0.146 P(F) = 0.879 P(EN F) = 0.122 a. Use the given probability information to set up a hypo- thetical 1000 table with columns corresponding to E and not E and rows corresponding to F and not F. b. Use the table from Part (a) to find the following
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