5.21 A study was conducted of 90 adult male patients following a new treatment for congestive heart failure. One of the variables measured on the patients was the increase in exercise capacity (in minutes) over a 4-week treatment period. The previous treatment regime had produced an average increase of u = 2 minutes. The researchers wanted to evaluate whether the new treatment had increased the value of u in comparison to the previous treatment. The data yielded y = 2.17 and s = 1.05. a. Using a = .05, what conclusions can you draw about the research hypothesis? b. What is the probability of making a Type II error if the actual value of u is 2.1?
5.21 A study was conducted of 90 adult male patients following a new treatment for congestive heart failure. One of the variables measured on the patients was the increase in exercise capacity (in minutes) over a 4-week treatment period. The previous treatment regime had produced an average increase of u = 2 minutes. The researchers wanted to evaluate whether the new treatment had increased the value of u in comparison to the previous treatment. The data yielded y = 2.17 and s = 1.05. a. Using a = .05, what conclusions can you draw about the research hypothesis? b. What is the probability of making a Type II error if the actual value of u is 2.1?
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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
Transcribed Image Text:5.21 A study was conducted of 90 adult male patients following a new treatment for congestive
heart failure. One of the variables measured on the patients was the increase in exercise capacity
(in minutes) over a 4-week treatment period. The previous treatment regime had produced
an average increase of u = 2 minutes. The researchers wanted to evaluate whether the new
treatment had increased the value of u in comparison to the previous treatment. The data yielded
y = 2.17 and s = 1.05.
a. Using a = .05, what conclusions can you draw about the research hypothesis?
b. What is the probability of making a Type II error if the actual value of u is 2.1?

Transcribed Image Text:QUESTION 4
5.21a: Select the correct reason and conclusion
Hint: See L-11 pdf and lecture, page 7-8
O 1. Zob = 1.54<1.645 = z0.05 --> fail to reject Ho. There is significant evidence to support the hypothesis that the mean has increased from 2.
O II. Zob = 1.54<1.645 = z0.05 --> reject Ho. There is significant evidence to support the hypothesis that the mean has increased from 2.
O III.zob = 1.74<1.645 = z0.05 --> reject Ho. There is significant evidence to support the hypothesis that the mean has increased from 2.
= 1.54 1.645 = Z0.05 --> fail to reject Ho. There is not significant evidence to support the hypothesis that the mean has increased from 2
O N.Zob
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