5.15 A cut slope was excavated in a saturated clay with a slope angle, B = 48; with the horizontal. Slope failure occured when the cut reached a depth of 10 m. Previous soil explorations showed that a rock layer was located at a depth of 14 m below the ground surface. Assuming an undrained condition and y = 17 kN/m²: a. Determine the undrained cohesion of the clay (Figure 15.13). b. What was the nature of the critical circle? c. With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?

Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
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Chapter16: Lateral Earth Pressure
Section: Chapter Questions
Problem 16.4P: In Problem 16.3, if there was a surcharge of 20 kN/m2 at the ground level, what would be the total...
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Please answer 15.15

For B> 53":
All circles are toe circles.
For B< 53":
Toe circle -
DH
Midpoint circle
Slope cirele
(a)
0.3
0.2
B= 53.
D = 00
4.0
0.1
1.2
15 2.0-
1.0
0.0
90
80
70
60
50
40
30
20
10
Slope angle, B (deg)
(b)
Figure 15.13 (a) Definition of parameters for midpoint circle type of failure; (b) plot of stability
number against slope angle (Adapted from Terzaghi and Peck, 1967. With permission of John Wiley
& Sons, Inc.)
Stability number, m
Transcribed Image Text:For B> 53": All circles are toe circles. For B< 53": Toe circle - DH Midpoint circle Slope cirele (a) 0.3 0.2 B= 53. D = 00 4.0 0.1 1.2 15 2.0- 1.0 0.0 90 80 70 60 50 40 30 20 10 Slope angle, B (deg) (b) Figure 15.13 (a) Definition of parameters for midpoint circle type of failure; (b) plot of stability number against slope angle (Adapted from Terzaghi and Peck, 1967. With permission of John Wiley & Sons, Inc.) Stability number, m
15.15 A cut slope was excavated in a saturated clay with a slope angle, B = 48; with the
horizontal. Slope failure occurred when the cut reached a depth of 10 m. Previous
soil explorations showed that a rock layer was located at a depth of 14 m below the
ground surface. Assuming an undrained condition and y = 17 kN/m':
a. Determine the undrained cohesion of the clay (Figure 15.13).
b. What was the nature of the critical circle?
c. With reference to the top of the slope, at what distance did the surface of the
sliding intersect the bottom of the excavation?
Transcribed Image Text:15.15 A cut slope was excavated in a saturated clay with a slope angle, B = 48; with the horizontal. Slope failure occurred when the cut reached a depth of 10 m. Previous soil explorations showed that a rock layer was located at a depth of 14 m below the ground surface. Assuming an undrained condition and y = 17 kN/m': a. Determine the undrained cohesion of the clay (Figure 15.13). b. What was the nature of the critical circle? c. With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
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