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5.15 A 36, 208 V, 60 Hz, 20 hp, four-pole induction motor has the following equivalent circuit para- meters. R1 = 0.12 2 R, = 0.1 2 X1 = X = 0.25 2 Xm = 10.0 2 The rotational loss is 400 W. For 5% slip, determine (a) The motor speed in rpm and radians per sec. (b) The motor current. (c) The stator cu-loss.

5.15 A 36, 208 V, 60 Hz, 20 hp, four-pole induction motor has the following equivalent circuit para- meters. R1 = 0.12 2 R, = 0.1 2 X1 = X = 0.25 2 Xm = 10.0 2 The rotational loss is 400 W. For 5% slip, determine (a) The motor speed in rpm and radians per sec. (b) The motor current. (c) The stator cu-loss.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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5.15 A 36, 208 V, 60 Hz, 20 hp, four-pole induction motor has the following equivalent circuit para- meters. R1 = 0.12 2 R, = 0.1 2 X1 = X = 0.25 2 Xm = 10.0 2 The rotational loss is 400 W. For 5% slip, determine (a) The motor speed in rpm and radians per sec. (b) The motor current. (c) The stator cu-loss. (d) The air gap power. (e) The rotor cu-loss. (f) The shaft power. (g) The developed torque and the shaft torque. (h) The efficiency. Use the IEEE-recommended equivalent circuit (Fig. 5.15).
Transcribed Image Text:5.15 A 36, 208 V, 60 Hz, 20 hp, four-pole induction motor has the following equivalent circuit para- meters. R1 = 0.12 2 R, = 0.1 2 X1 = X = 0.25 2 Xm = 10.0 2 The rotational loss is 400 W. For 5% slip, determine (a) The motor speed in rpm and radians per sec. (b) The motor current. (c) The stator cu-loss. (d) The air gap power. (e) The rotor cu-loss. (f) The shaft power. (g) The developed torque and the shaft torque. (h) The efficiency. Use the IEEE-recommended equivalent circuit (Fig. 5.15).
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