5.0 m 5.50 m 6.0 m 7.0 m 5.0 m (1b0+SN) KN 144 KN E G 120 KN _96 kN M IN 5.0 m 4.50 m 4.20 m 4.0 m
5.0 m 5.50 m 6.0 m 7.0 m 5.0 m (1b0+SN) KN 144 KN E G 120 KN _96 kN M IN 5.0 m 4.50 m 4.20 m 4.0 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
note: SN is equal to 18, topload will now be 118kN
![3. Factor Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W and X
are rigid supports.
Determine the following.
a) The shear forces in columns and girders.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F199550ec-e46d-47ca-ac02-29ef09665bc9%2F1f111c8b-8f4e-4260-a0fb-c0a957a5b786%2F2x7xx7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Factor Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W and X
are rigid supports.
Determine the following.
a) The shear forces in columns and girders.
![5.0 m
5.50 m
6.0 m
7.0 m
5.0 m
(1b0+SN) KN >
B
144 kN
120 KN
96 KN
M
IN
5.0 m
4.50 m
4.20 m
I 4.0 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F199550ec-e46d-47ca-ac02-29ef09665bc9%2F1f111c8b-8f4e-4260-a0fb-c0a957a5b786%2Fl2hq18_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5.0 m
5.50 m
6.0 m
7.0 m
5.0 m
(1b0+SN) KN >
B
144 kN
120 KN
96 KN
M
IN
5.0 m
4.50 m
4.20 m
I 4.0 m
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