5. y" – 3y' +2y=0; y1 =e*, y2 = e2x; y(0) =1, y'(0) =0 %3D -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Answer 5 Please and thank you.

3. y" +4y = 0; yıi =cos 2x, y2 = sin 2x; y(0) = 3, y'(0) =8
4. y" + 25y = 0; yı = cos 5x, y2 = sin 5x; y(0) = 10,
y'(0) = -10
5. y" – 3y' +2y = 0; y1 = e*, y2 = e2x; y(0) = 1, y'(0) = 0
%3D
%3D
%3D
Transcribed Image Text:3. y" +4y = 0; yıi =cos 2x, y2 = sin 2x; y(0) = 3, y'(0) =8 4. y" + 25y = 0; yı = cos 5x, y2 = sin 5x; y(0) = 10, y'(0) = -10 5. y" – 3y' +2y = 0; y1 = e*, y2 = e2x; y(0) = 1, y'(0) = 0 %3D %3D %3D
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