5. Write the Assembly language program to continually read a value on an input port whose address is 100. If the number represented by the data on the input port is greater than 50, move 80H to the output port whose address is 101. If the number is less than 50, move 10H to the output port whose address is 101. ;data INPORT: EQU 100 ; input port OUTPORT : EQU 101 ; output port EQU 50 ; set point SETPT: ;code START : IN INPORT ; read the input port ; compare ; continue if the same ; jump on positive (greater) ; jump on minus (smaller) CPI SETPT JZ LOOP JP SUB1 JM SUB2 HLT ; move 80H to Accumulator ; output to port ; continue ; move 10H to accumulator ; output to port ; continue SUB1: MVI A, 80H OUT OUTPORT JMP START SUB2: MVI A, 10H OUT OUTPORT JMP START
5. Write the Assembly language program to continually read a value on an input port whose address is 100. If the number represented by the data on the input port is greater than 50, move 80H to the output port whose address is 101. If the number is less than 50, move 10H to the output port whose address is 101. ;data INPORT: EQU 100 ; input port OUTPORT : EQU 101 ; output port EQU 50 ; set point SETPT: ;code START : IN INPORT ; read the input port ; compare ; continue if the same ; jump on positive (greater) ; jump on minus (smaller) CPI SETPT JZ LOOP JP SUB1 JM SUB2 HLT ; move 80H to Accumulator ; output to port ; continue ; move 10H to accumulator ; output to port ; continue SUB1: MVI A, 80H OUT OUTPORT JMP START SUB2: MVI A, 10H OUT OUTPORT JMP START
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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