5. Which of the following are true and which false? Give reasons for each of your answers. (a) It is possible to find a pair of five-dimensional subspaces S and T of R® such that SNT = {0}. (b) If none of the eigenvalues of a square matrix is 0, then it is invertible. (c) If an n by n matrix does not have n distinct eigenvalues then it is not diagonalizable.
5. Which of the following are true and which false? Give reasons for each of your answers. (a) It is possible to find a pair of five-dimensional subspaces S and T of R® such that SNT = {0}. (b) If none of the eigenvalues of a square matrix is 0, then it is invertible. (c) If an n by n matrix does not have n distinct eigenvalues then it is not diagonalizable.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:**Linear Algebra Problem Set**
**Problem 5: True or False Analysis**
Analyze the following statements and determine which are true and which are false. Provide justifications for each of your answers.
(a) **It is possible to find a pair of five-dimensional subspaces \( S \) and \( T \) of \(\mathbb{R}^8\) such that \( S \cap T = \{0\} \).**
(b) **If none of the eigenvalues of a square matrix is 0, then it is invertible.**
(c) **If an \( n \) by \( n \) matrix does not have \( n \) distinct eigenvalues, then it is not diagonalizable.**
(d) **Let \( M \) be a 2 by 2 invertible matrix. Let \( S \) be the set of all 2 by 2 matrices \( A \) that are diagonalized by \( M \). That is, \( M^{-1}AM \) is diagonal for any such matrix \( A \) in the set \( S \). True or False: \( S \) is a subspace of the vector space of 2 by 2 matrices.**
(e) **Let \( M \) be a 2 by 2 invertible matrix which diagonalizes both \( A \) and \( B \). Then \( M \) does not necessarily diagonalize \( AB \).**
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