**Question 5: Equivalent Resistance Calculation****Problem Statement:**What is the equivalent resistance in the circuit shown in the figure?**Circuit Diagram Explanation:**The circuit consists of four resistors connected in a specific combination:- \(R_1 = 10 \, \Omega\)- \(R_2 = 20 \, \Omega\)- \(R_3 = 20 \, \Omega\)- \(R_4 = 30 \, \Omega\)The resistors are arranged as follows:- Resistors \(R_2\) and \(R_3\) are in parallel.- \(R_1\) is in series with the equivalent resistance of \(R_2\) and \(R_3\).- \(R_4\) is in series with the combination of \(R_1\), \(R_2\), and \(R_3\).**Answer Choices:**a) \(80 \, \Omega\) b) \(55 \, \Omega\) c) \(50 \, \Omega\) d) \(35 \, \Omega\) **Calculation Method:**1. Calculate the equivalent resistance of \(R_2\) and \(R_3\) in parallel: \[ \frac{1}{R_{23}} = \frac{1}{R_2} + \frac{1}{R_3} = \frac{1}{20} + \frac{1}{20} = \frac{2}{20} = \frac{1}{10} \] \[ R_{23} = 10 \, \Omega \]2. Add the result to \(R_1\) since they are in series: \[ R_{123} = R_1 + R_{23} = 10 + 10 = 20 \, \Omega \]3. Add \(R_4\) in series: \[ R_{\text{equivalent}} = R_{123} + R_4 = 20 + 30 = 50 \, \Omega \]**Correct Answer:** c) \(50 \, \Omega\)

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Answered: 5. What is the equivalent resistance in…

5. What is the equivalent resistance in the circuit shown in the figure? = 10 Ω a) 80 Ω b) 55 Ω c) 50 Ω d) 35 Ω R R2 = 20 Ω www R4 = 30 Ω R, = 20 Ω

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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