5. Using your video and estimating a scale, comment on how accurate your calculatic of maximum height is. Write out all your work and assumptions, ie. using your height, you estimate the height of the ball to be twice your height).
5. Using your video and estimating a scale, comment on how accurate your calculatic of maximum height is. Write out all your work and assumptions, ie. using your height, you estimate the height of the ball to be twice your height).
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please help with #5 question 4 was answered previously thank you!

Transcribed Image Text:4. MAXIMUM HEIGHT OF BALL:
Using equation of motion, distance travelled in vertical
direction:
H=uT + gT2
H=0. T +
gT²
H=}gr²
Put the value of time required to reach the maximum
height i.e. half of time of flight:
u sin 0
H=;g(usin e
H=u2 sin?
2g

Transcribed Image Text:2. From your video, step through it frame by frame and record the time from the moment
the ball leaves your hand. Then make note of the time right before the ball comes
back to your hand. Find the time of flight of the ball and write out all your work below.
Time the ball left hand: 00:002
Time ball returned to hand: 00:10
3. Making some assumptions about the initial and final velocities, derive an equation for
finding the velocity from the time of flight you measured in #2. Write out all your work.
(HINT: Vo = -V)
2u sin 0
T =
%3D
8.
Tg= 2u sin e
Tg
la
2 sin A
4. From the information you have, derive the maximum height of the ball you threw.
Write out all the work in the space below.
bn
5. Using your video and estimating a scale, comment on how accurate your calculation
of maximum height is. Write out all your work and assumptions, ie. using your
height, you estimate the height of the ball to be twice your height).
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