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5. Using Stokes' theorem, find I (VxF) ndo, where F yi+xj+(y+z) k and S is the portion of the surface 2x+y+z=2 above the first octant and n is the unitary normal vector to the surface, with non-negative z component.

5. Using Stokes' theorem, find I (VxF) ndo, where F yi+xj+(y+z) k and S is the portion of the surface 2x+y+z=2 above the first octant and n is the unitary normal vector to the surface, with non-negative z component.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please answer question 5 only. Thanks
1. True/False: V. (V x F) = 0. (Justify your answer by showing it is true or false for vector fields of the form F = Fi + Gj.) = V x G, then F G. (Justify 2. True/False: If F, G are vector fields and V x F your answer by using the properties of curl.) 3. True/False: If F is conservative then V F = 0. (Justify your answer.) . 4. True/False: curl(divF)) is not a meaningful expression. (Justify your answer.) 5. Using Stokes' theorem, find I (VxF) ndo, where F = yi+xj+(y+z) k and S is the portion of the surface 2r+y+z= 2 above the first octant and n is the unitary normal vector to the surface, with non-negative z com nt.
Transcribed Image Text:1. True/False: V. (V x F) = 0. (Justify your answer by showing it is true or false for vector fields of the form F = Fi + Gj.) = V x G, then F G. (Justify 2. True/False: If F, G are vector fields and V x F your answer by using the properties of curl.) 3. True/False: If F is conservative then V F = 0. (Justify your answer.) . 4. True/False: curl(divF)) is not a meaningful expression. (Justify your answer.) 5. Using Stokes' theorem, find I (VxF) ndo, where F = yi+xj+(y+z) k and S is the portion of the surface 2r+y+z= 2 above the first octant and n is the unitary normal vector to the surface, with non-negative z com nt.
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