5. Use polar coordinates to find each limit : x³ + y³ lim (x,y) →(0,0) x² + y² (a) (b) lim (x,y) → (0,0) (x² + y²) In (x² + y²).
5. Use polar coordinates to find each limit : x³ + y³ lim (x,y) →(0,0) x² + y² (a) (b) lim (x,y) → (0,0) (x² + y²) In (x² + y²).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Calculus
![5. Use polar coordinates to find each limit:
x³ + y³
(x,y) →(0,0) x² + y²
(a) lim
(b)
lim
(x,y) →(0,0)
(x² + y²) In (x² + y²).
xy
6. Explain why the path y = x cannot be used to evaluate the limit
lim
(x,y) →(1,0) √x −1+y]
Do not evaluate the limit. Just explain why you cannot use y = x as a path.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1784d6b6-d0da-4ca6-88bb-f1a2aff3fb92%2F21069747-a07d-4674-8ccc-9374763233ea%2Fj8zcsgt_processed.png&w=3840&q=75)
Transcribed Image Text:5. Use polar coordinates to find each limit:
x³ + y³
(x,y) →(0,0) x² + y²
(a) lim
(b)
lim
(x,y) →(0,0)
(x² + y²) In (x² + y²).
xy
6. Explain why the path y = x cannot be used to evaluate the limit
lim
(x,y) →(1,0) √x −1+y]
Do not evaluate the limit. Just explain why you cannot use y = x as a path.
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