Can someone please explain it to me ASAP?!!! This is periodic motion **Problem: Determining the Frequency of Oscillation****Question:**The two springs from the problem above are reconnected to mass \( m \) as shown. Now, what is the frequency of oscillation?**Diagram:**The diagram shows a mass \( m \) connected between two springs with spring constants \( k_1 \) and \( k_2 \). The spring \( k_1 \) is attached to the left of the mass, and the spring \( k_2 \) is attached to the right of the mass. Both springs are fixed at the opposite ends, forming a horizontal system.To determine the frequency of oscillation (\( \omega \)) of the mass \( m \), we can start by noting that the springs are in series. The effective spring constant \( k \) of two springs in series is given by:\[\frac{1}{k} = \frac{1}{k_1} + \frac{1}{k_2}\]Simplifying this, we get:\[k = \frac{k_1 k_2}{k_1 + k_2}\]The frequency of oscillation is given by the formula:\[\omega = \sqrt{\frac{k}{m}}\]Substituting the effective spring constant \( k \) into the equation, we obtain the frequency of oscillation:\[\omega = \sqrt{\frac{\frac{k_1 k_2}{k_1 + k_2}}{m}} = \sqrt{\frac{k_1 k_2}{m(k_1 + k_2)}}\]Thus, the frequency of oscillation for the mass \( m \) connected to two springs with spring constants \( k_1 \) and \( k_2 \) is:\[\boxed{\omega = \sqrt{\frac{k_1 k_2}{m(k_1 + k_2)}}}\]This formula allows us to find the natural frequency of the system based on the given spring constants and mass.

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Answered: 5. The two springs from the problem…

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5. The two springs from the problem above are reconnected to mass m as shown. Now what is the frequency of oscillation? 2 ellue m Fee ull