5. The slope field for the system = 2r + by D. 2r – 2y is shown to the right. The eigenvalues of the coefficient matrix are found to be A, = 4 and Ay=-4 and their corresponding eigenvectors are V, = (3, 1) and Va = (1, -1), respectively. (a) Determine the type of the equilibrium point at the origin. (b) Calculate all straight-line solutions. (e) Plot the z(t)- and y(t)-graphs for t2 0 for the ICs: B= (3, 1).
5. The slope field for the system = 2r + by D. 2r – 2y is shown to the right. The eigenvalues of the coefficient matrix are found to be A, = 4 and Ay=-4 and their corresponding eigenvectors are V, = (3, 1) and Va = (1, -1), respectively. (a) Determine the type of the equilibrium point at the origin. (b) Calculate all straight-line solutions. (e) Plot the z(t)- and y(t)-graphs for t2 0 for the ICs: B= (3, 1).
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.7: The Inverse Of A Matrix
Problem 31E
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![5. The slope field for the system
de
= 2r + 6y
2r - 2y
dt
is shown to the right. The eigenvalues of the coefficient matrix are found to be
A = 4 and Az = -4 and their corresponding eigenvectors are V, (3, 1) and
Va = (1, -1), respectively.
(a) Determine the type of the equilibrium point at the origin.
(b) Calculate all straight-line solutions.
(c) Plot the z(t)- and y(t)-graphs for t 2 0 for the ICs: B= (3, 1).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47d75510-4ebd-4697-855e-74b376eac56f%2F6b4b451c-ef59-4ebb-916f-c573be374ffc%2Frn3cy8b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. The slope field for the system
de
= 2r + 6y
2r - 2y
dt
is shown to the right. The eigenvalues of the coefficient matrix are found to be
A = 4 and Az = -4 and their corresponding eigenvectors are V, (3, 1) and
Va = (1, -1), respectively.
(a) Determine the type of the equilibrium point at the origin.
(b) Calculate all straight-line solutions.
(c) Plot the z(t)- and y(t)-graphs for t 2 0 for the ICs: B= (3, 1).
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