5. The results of a particle size analysis of a soil are given in the following table. The Atterberglimit tests yielded LL=62, PL = 20.Sieve Opening (mm)Percent Coarser by WeightSieve No.4.755.1102.0010.0200.850.42540.74070.284.890.5600.251000.15200Pan0.075100a) Draw the gradation curve for this soilb) Determine the uniformity coefficient and the coefficient of curvaturec) Classify the soil using USCS and ASSHTOd) Rate this soil as a subgrade for highway construction

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Answered: 5. The results of a particle size…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Problem 2 A sample was shaken through a nest of sieves and the results are obtained. The initial soil mass of the soil sample is 500g. Draw the particle size distribution curves and interpret the graph. Mass Retained Sieve No. Diameter (mm) (gram) 4 4.75 0 10 2.00 40.2 20 0.85 84.6 30 0.6 50.2 40 0.425 40.0 60 0.25 106.4 140 0.106 108.8 200 0.075 59.4 Pan 8.7 Determine the: 6. Percentage Loss in Soil Mass 7. Particle Size (%Gravel, % Sand, % Silt and %Clay) according to USCS 8. Effective Grain Size (D10) 9. Coefficient of Uniformity (Cu) 10. Coefficient of Curvature/Gradient (Cc)
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Situation 3. Following are the results of a sieve analysis. Determine: a. Cu b. Cc c. So Sieve No. 4 6 10 20 40 60 100 200 Pan Diameter (mm) 4.760 2.380 2.000 0.840 0.420 0.250 0.149 0.074 Soil Sample Mass Retained (g) 100 180 86 160 105 134 110 65 45
Question 44 The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 No. 8 No. 10 No. 20 4.760 96 2.380 80 2.000 78 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 45 PL 36 General classification Granular materials (35% or less of total sample passing No. 200) A-I A-2 Group classification A-l-a A-1-5 A3 A-24 A-25 A-2-6 A-2-7 Sieve analysis (percent passing) No. 10 No. 40 No. 200 50 max. 30 max. 15 max. 50 max. 25 max. 51 min. 10 max. 35 max. 35 max. 35 max. 35 max. Characteristics of fraction passing No. 40 Liquid limit Plasticity index 40 max. 41 min. 40 max. 41 min. 6 max. NP 10 max. 10 max. 11 min. 11 min. Usual types of significant Stone fragments, gravel, and sand Fine Silty or clayey gravel and sand sand
Given below is the result of a sieve analysis done on a soil sample.Sieve No. Diameter Percent Passing %4 4.750 9510 2.000 8220 0.850 7340 0.425 5360 0.250 23100 0.150 14200 0.075 7Pan --- 0Determine the value of the coefficient of uniformity
SG is 2.66 and temperature is 18 degrees celcius
Given below is the result of a sieve analysis done on a soil sample. Sieve No. Diameter Percent Passing % 4 4.750 96 10 2.000 81 20 0.850 72 40 0.425 50 60 0.250 27 100 0.150 14 200 0.075 5 Pan --- 0 Determine the value of the coefficient of gradation/curvature.
5. The following information is obtained from a sieve analysis to determine the range of particle sizes in a granular soil sample. Sieve Size Sieve Opening (4.76) Percent Finer#4 4.76 96#10 2.00 80#20 0.84 51#40 0.42 38#60 0.25 25#100 0.149 12#200 0.074 5 Present the information as grain-size curve on semi-logarithmic coordinates of percent finer against particle size diameter. From the plot, determine the uniformity coefficient Cu.
2.8 2.7 The following are the results of a sieve and hydrometer analysis. Sieve number/ grain size Analysis Sieve Hydrometer Analysis Sieve 40 80 170 200 0.04 mm 0.02 mm 0.01 mm 0.005 mm 0.0015 mm Hydrometer Sieve number/ grain size Percent finer than a. Draw the grain-size distribution curve. b. Determine the percentages of gravel, sand, silt, and clay according to the MIT system. c. Repeat Part b according to the USDA system. d. Repeat Part b according to the AASHTO system. Repeat Problem 2.7 with the following data: 20 30 40 60 80 200 0.05 mm 0.03 mm 0.015 mm 0.006 mm 0.004 mm 0.0015 mm 100 96 85 80 59 39 26 15 8 Cengage Learning 2014 Percent finer than 100 96 90 76 65 34 27 19 11 7 6 5 Ⓒ Cengage Learning 2014
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The results of the sieve analysis done on a soil are shown below. Sieve No. Diameter Soil A 4 4.760 88 6 2.380 69 10 2.000 62 20 0.840 51 40 0.420 39 60 0.250 31 100 0.149 18 200 0.074 14 LL 60 PL 20 Determine its classification using USCS. SC SM ML None of the above. CL

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