5. The National Student Loan Survey selected a random sample of 1,280 borrowers who began repayment of their loans between four and six months prior to the study. The sample mean debt for undergraduate study was $18,900 and the standard deviation was about $49,000. (Note that this distribution is clearly skewed to the right, but because our sample size is quite large, we can rely on the central limit theorem to assure us that the sampling distribution of the sample mean is approximately normal.) a. Compute a 95% confidence interval for the true mean debt for all undergraduate borrowers. b. Suppose we wanted a more precise estimate, with a margin of error of just ±$2,000. How big a sample would we need to achieve this margin of error with a 95% level of confidence?
5. The National Student Loan Survey selected a random sample of 1,280 borrowers who began repayment of their loans between four and six months prior to the study. The sample mean debt for undergraduate study was $18,900 and the standard deviation was about $49,000. (Note that this distribution is clearly skewed to the right, but because our sample size is quite large, we can rely on the central limit theorem to assure us that the sampling distribution of the sample mean is approximately normal.) a. Compute a 95% confidence interval for the true mean debt for all undergraduate borrowers. b. Suppose we wanted a more precise estimate, with a margin of error of just ±$2,000. How big a sample would we need to achieve this margin of error with a 95% level of confidence?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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
Transcribed Image Text:5. The National Student Loan Survey selected a random sample of 1,280 borrowers who began
repayment of their loans between four and six months prior to the study. The sample mean debt for
undergraduate study was $18,900 and the standard deviation was about $49,000. (Note that this
distribution is clearly skewed to the right, but because our sample size is quite large, we can rely on
the central limit theorem to assure us that the sampling distribution of the sample mean is
approximately normal.)
а.
Compute a 95% confidence interval for the true mean debt for all undergraduate borrowers.
b. Suppose we wanted a more precise estimate, with a margin of error of just ±$2,000. How big
a sample would we need to achieve this margin of error with a 95% level of confidence?
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