5. Suppose there exits positive differentiable a(x) and B(x) such that a*(x) – B°(x) = 3, and a'(x) = 53(x) (a) Assuming that a(x) exists (i.e., the inverse function of a(r) exists), compute an explicit formula for [a(x)]'. Hint: Follow the five step process we used to compute the derivative of In(x), arctan(x), etc.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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5. Suppose there exits positive differentiable a(x) and B(x) such that
a (x) – B° (x) = 3, and
a'(x) = 58(x)
(a) Assuming that a-1(x) exists (i.e., the inverse function of a(x) exists), compute an explicit
formula for [a(x)]'. Hint: Follow the five step process we used to compute the derivative
of In(x), arctan(x), etc.
(b) (Harder) Assuming that B-'(x) exists (i.e., the inverse function of 3(x) exists), compute
an explicit formula for [3-1(x)]'. Hint: Same basic idea as part (a), but you may need to
differentiate the first property to generate a way to convert B's into as.
Transcribed Image Text:5. Suppose there exits positive differentiable a(x) and B(x) such that a (x) – B° (x) = 3, and a'(x) = 58(x) (a) Assuming that a-1(x) exists (i.e., the inverse function of a(x) exists), compute an explicit formula for [a(x)]'. Hint: Follow the five step process we used to compute the derivative of In(x), arctan(x), etc. (b) (Harder) Assuming that B-'(x) exists (i.e., the inverse function of 3(x) exists), compute an explicit formula for [3-1(x)]'. Hint: Same basic idea as part (a), but you may need to differentiate the first property to generate a way to convert B's into as.
Expert Solution
Step 1: Part a)

Given: α3x - β3x = 3                                                    1       α'x          =5βx                                             2--------------------------To derive explicit formula for α-1x'. 

Let say, α-1x = t                                                                 3We need to find expression for dtdx.-------------------------From 3 x=αtDifferentiatew.r.t. x1=α't.dtdxdtdx=1α'tReplace't'using 3ddxα-1x=1α'α-1xHence α-1x'=1α'α-1x

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